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新人教版高中英语选修2Unit 1 Science and Scientists-Reading and thinking教学设计
Step 5： After learning the text, discuss with your peers about the following questions:1.John Snow believed Idea 2 was right. How did he finally prove it?2. Do you think John Snow would have solved this problem without the map?3. Cholera is a 19th century disease. What disease do you think is similar to cholera today?SARS and Covid-19 because they are both deadly and fatally infectious, have an unknown cause and need serious public health care to solve them urgently.keys:1. John Snow finally proved his idea because he found an outbreak that was clearly related to cholera, collected information and was able to tie cases outside the area to the polluted water.2. No. The map helped John Snow organize his ideas. He was able to identify those households that had had many deaths and check their water-drinking habits. He identified those houses that had had no deaths and surveyed their drinking habits. The evidence clearly pointed to the polluted water being the cause.3. SARS and Covid-19 because they are both deadly and fatally infectious, have an unknown cause and need serious public health care to solve them urgently.Step 6: Consolidate what you have learned by filling in the blanks:John Snow was a well-known _1___ in London in the _2__ century. He wanted to find the _3_____ of cholera in order to help people ___4_____ it. In 1854 when a cholera __5__ London, he began to gather information. He ___6__ on a map ___7___ all the dead people had lived and he found that many people who had ___8____ (drink) the dirty water from the __9____ died. So he decided that the polluted water ___10____ cholera. He suggested that the ___11__ of all water supplies should be _12______ and new methods of dealing with ____13___ water be found. Finally, “King Cholera” was __14_____.Keys: 1. doctor 2. 19th 3.cause 4.infected with 5.hit 6.marked 7.where 8.drunk 9.pump 10.carried 11.source 12.examined 13.polluted 14.defeatedHomework: Retell the text after class and preview its language points
新人教版高中英语选修2Unit 1 Science and Scientists-Using langauge教学设计
This happens because the dish soap molecules have a strong negative charge, and the milk molecules have a strong positive charge. Like magnets, these molecules are attracted to each other, and so they appear to move around on the plate, taking the food coloring with them, making it look like the colors are quickly moving to escape from the soap.Listening text:? Judy: Oh, I'm so sorry that you were ill and couldn't come with us on our field trip. How are you feeling now? Better?? Bill: Much better, thanks. But how was it?? Judy: Wonderful! I especially liked an area of the museum called Light Games.it was really cool. They had a hall of mirrors where I could see myself reflected thousands of times!? Bill: A hall of mirrors can be a lot of fun. What else did they have?? Judy: Well, they had an experiment where we looked at a blue screen for a while, and then suddenly we could see tiny bright lights moving around on it. You'll never guess what those bright lights were!? Bill: Come on, tell me!? Judy: They were our own blood cells. For some reason, our eyes play tricks on us when we look at a blue screen, and we can see our own blood cells moving around like little lights! But there was another thing I liked better. I stood in front of a white light, and it cast different shadows of me in every color of the rainbow!? Bill: Oh, I wish I had been there. Tell me more!? Judy: Well, they had another area for sound. They had a giant piano keyboard that you could use your feet to play. But then, instead of playing the sounds of a piano, it played the voices of classical singers! Then they had a giant dish, and when you spoke into it, it reflected the sound back and made it louder. You could use it to speak in a whisper to someone 17 meters away.? Bill: It all sounds so cool. I wish I could have gone with you? Judy: I know, but we can go together this weekend. I'd love to go there again!? Bill: That sounds like a great idea!
新人教版高中英语选修2Unit 2 Bridging Cultures-Discovering useful structures教学设计
The grammar of this unit is designed to review noun clauses. Sentences that use nouns in a sentence are called noun clauses. Nominal clauses can act as subject, object, predicate, appositive and other components in compound sentences. According to the above-mentioned different grammatical functions, nominal clauses are divided into subject clause, object clause, predicate clause and appositive clause. In this unit, we will review the three kinds of nominal clauses. Appositive clauses are not required to be mastered in the optional compulsory stage, so they are not involved.1. Guide the students to judge the compound sentences and determine the composition of the clauses in the sentence.2. Instruct students to try to learn grammar by generalizing grammar rules, controlling written practice, and semi-open oral output.3. Inspire the students to systematize the function and usage of noun clause1.Instruct students to try to learn grammar by generalizing grammar rules, controlling written practice, and semi-open oral output.2.Inspire the students to systematize the function and usage of noun clauseStep1: The teacher ask studetns to find out more nominal clauses from the reading passage and udnerline the nominal clauses.
新人教版高中英语选修2Unit 3 Food and Culture-Discovering useful structures教学设计
The newspaper reported more than 100 people had been killed in the thunderstorm.报纸报道说有一百多人在暴风雨中丧生。(2)before、when、by the time、until、after、once等引导的时间状语从句的谓语是一般过去时，以及by、before后面接过去的时间时，主句动作发生在从句的动作或过去的时间之前且表示被动时，要用过去完成时的被动语态。By the time my brother was 10, he had been sent to Italy.我弟弟10岁前就已经被送到意大利了。Tons of rice had been produced by the end of last month. 到上月底已生产了好几吨大米。(3) It was the first/second/last ... time that ...句中that引导的定语从句中，主语与谓语构成被动关系时，要用过去完成时的被动语态。It was the first time that I had seen the night fact to face in one and a half years. 这是我一年半以来第一次亲眼目睹夜晚的景色。(4)在虚拟语气中，条件句表示与过去事实相反，且主语与谓语构成被动关系时，要用过去完成时的被动语态。If I had been instructed by him earlier, I would have finished the task.如果我早一点得到他的指示，我早就完成这项任务了。If I had hurried, I wouldn't have missed the train.如果我快点的话，我就不会误了火车。If you had been at the party, you would have met him. 如果你去了晚会，你就会见到他的。
新人教版高中英语选修2Unit 3 Food and Culture-Reading and thinking教学设计
The discourse explores the link between food and culture from a foreign’s perspective and it records some authentic Chinese food and illustrates the cultural meaning, gerography features and historic tradition that the food reflects. It is aimed to lead students to understand and think about the connection between food and culture. While teaching, the teacher should instruct students to find out the writing order and the writer’s experieces and feelings towards Chinese food and culture.1.Guide the students to read the text, sort out the information and dig out the topic.2.Understand the cultural connotation, regional characteristics and historical tradition of Chinese cuisine3.Understand and explore the relationship between food and people's personality4.Guide the students to use the cohesive words in the text5.Lead students to accurately grasp the real meaning of the information and improve the overall understanding ability by understanding the implied meaning behind the text.1. Enable the Ss to understand the structure and the writing style of the passage well.2. Lead the Ss to understand and think further about the connection between food and geography and local character traits.Step1: Prediction before reading. Before you read, look at the title, and the picture. What do you think this article is about?keys:It is about various culture and cuisine about a place or some countries.
人教版高中数学选择性必修二变化率问题教学设计
导语在必修第一册中，我们研究了函数的单调性，并利用函数单调性等知识，定性的研究了一次函数、指数函数、对数函数增长速度的差异，知道“对数增长” 是越来越慢的，“指数爆炸” 比“直线上升” 快得多，进一步的能否精确定量的刻画变化速度的快慢呢，下面我们就来研究这个问题。新知探究问题1 高台跳水运动员的速度高台跳水运动中，运动员在运动过程中的重心相对于水面的高度h(单位：m)与起跳后的时间t(单位：s)存在函数关系h(t)＝－4.9t2＋4.8t＋11.如何描述用运动员从起跳到入水的过程中运动的快慢程度呢？直觉告诉我们，运动员从起跳到入水的过程中，在上升阶段运动的越来越慢，在下降阶段运动的越来越快，我们可以把整个运动时间段分成许多小段，用运动员在每段时间内的平均速度v ?近似的描述它的运动状态。
人教版高中数学选择性必修二导数的四则运算法则教学设计
求函数的导数的策略(1)先区分函数的运算特点，即函数的和、差、积、商，再根据导数的运算法则求导数；(2)对于三个以上函数的积、商的导数，依次转化为“两个”函数的积、商的导数计算．跟踪训练1 求下列函数的导数：(1)y＝x2＋log3x； (2)y＝x3·ex； (3)y＝cos xx.[解] (1)y′＝(x2＋log3x)′＝(x2)′＋(log3x)′＝2x＋1xln 3.(2)y′＝(x3·ex)′＝(x3)′·ex＋x3·(ex)′＝3x2·ex＋x3·ex＝ex(x3＋3x2)．(3)y′＝cos xx′＝?cos x?′·x－cos x·?x?′x2＝－x·sin x－cos xx2＝－xsin x＋cos xx2.跟踪训练2 求下列函数的导数（1）y＝tan x； （2）y＝2sin x2cos x2解析：（1）y＝tan x＝sin xcos x，故y′＝?sin x?′cos x－?cos x?′sin x?cos x?2＝cos2x＋sin2xcos2x＝1cos2x.（2）y＝2sin x2cos x2＝sin x，故y′＝cos x.例5 日常生活中的饮用水通常是经过净化的，随着水的纯净度的提高，所需进化费用不断增加，已知将1t水进化到纯净度为x%所需费用（单位：元），为c(x)=5284/(100-x) (80<x<100)求进化到下列纯净度时，所需进化费用的瞬时变化率：（1） 90% ；（2） 98%解：净化费用的瞬时变化率就是净化费用函数的导数；c^' (x)=〖(5284/(100-x))〗^'=(5284^’×(100-x)-"5284 " 〖(100-x)〗^’)/〖(100-x)〗^2 =(0×(100-x)-"5284 " ×(-1))/〖(100-x)〗^2 ="5284 " /〖(100-x)〗^2
人教版高中数学选修3成对数据的相关关系教学设计
由样本相关系数??≈0.97,可以推断脂肪含量和年龄这两个变量正线性相关，且相关程度很强。脂肪含量与年龄变化趋势相同.归纳总结1．线性相关系数是从数值上来判断变量间的线性相关程度，是定量的方法．与散点图相比较，线性相关系数要精细得多，需要注意的是线性相关系数r的绝对值小，只是说明线性相关程度低，但不一定不相关，可能是非线性相关．2．利用相关系数r来检验线性相关显著性水平时，通常与0.75作比较，若|r|>0.75，则线性相关较为显著，否则不显著．例2. 有人收集了某城市居民年收入(所有居民在一年内收入的总和)与A商品销售额的10年数据,如表所示.画出散点图，判断成对样本数据是否线性相关，并通过样本相关系数推断居民年收入与A商品销售额的相关程度和变化趋势的异同.
人教版高中数学选择性必修二导数的概念及其几何意义教学设计
新知探究前面我们研究了两类变化率问题：一类是物理学中的问题，涉及平均速度和瞬时速度；另一类是几何学中的问题，涉及割线斜率和切线斜率。这两类问题来自不同的学科领域，但在解决问题时，都采用了由“平均变化率”逼近“瞬时变化率”的思想方法；问题的答案也是一样的表示形式。下面我们用上述思想方法研究更一般的问题。探究1： 对于函数y=f(x) ，设自变量x从x_0变化到x_0+ ?x ，相应地，函数值y就从f(x_0)变化到f(〖x+x〗_0) 。这时， x的变化量为?x，y的变化量为?y=f(x_0+?x)-f(x_0)我们把比值?y/?x，即?y/?x=(f(x_0+?x)-f(x_0)" " )/?x叫做函数从x_0到x_0+?x的平均变化率。1．导数的概念如果当Δx→0时，平均变化率ΔyΔx无限趋近于一个确定的值，即ΔyΔx有极限，则称y＝f (x)在x＝x0处____，并把这个________叫做y＝f (x)在x＝x0处的导数(也称为__________)，记作f ′(x0)或________，即
人教版高中数学选择性必修二等比数列的概念 (2) 教学设计
二、典例解析例4. 用 10 000元购买某个理财产品一年.（1）若以月利率0.400%的复利计息，12个月能获得多少利息（精确到1元）？（2）若以季度复利计息，存4个季度，则当每季度利率为多少时，按季结算的利息不少于按月结算的利息（精确到10^(-5)）？分析：复利是指把前一期的利息与本金之和算作本金，再计算下一期的利息.所以若原始本金为a元，每期的利率为r ，则从第一期开始，各期的本利和a , a(1+r)，a(1+r)^2…构成等比数列.解：（1）设这笔钱存 n 个月以后的本利和组成一个数列{a_n }，则{a_n }是等比数列，首项a_1=10^4 (1+0.400%)，公比 q=1+0.400%，所以a_12=a_1 q^11 〖=10〗^4 (1+0.400%)^12≈10 490.7.所以，12个月后的利息为10 490.7-10^4≈491（元）.解：（2）设季度利率为 r ，这笔钱存 n 个季度以后的本利和组成一个数列{b_n }，则{b_n }也是一个等比数列，首项 b_1=10^4 (1+r)，公比为1+r，于是 b_4=10^4 (1+r)^4.
人教版高中数学选择性必修二等差数列的概念（1）教学设计
我们知道数列是一种特殊的函数，在函数的研究中，我们在理解了函数的一般概念，了解了函数变化规律的研究内容（如单调性，奇偶性等）后，通过研究基本初等函数不仅加深了对函数的理解，而且掌握了幂函数，指数函数，对数函数，三角函数等非常有用的函数模型。类似地，在了解了数列的一般概念后，我们要研究一些具有特殊变化规律的数列，建立它们的通项公式和前n项和公式，并应用它们解决实际问题和数学问题，从中感受数学模型的现实意义与应用，下面，我们从一类取值规律比较简单的数列入手。新知探究1.北京天坛圜丘坛，的地面有十板布置，最中间是圆形的天心石，围绕天心石的是9圈扇环形的石板，从内到外各圈的示板数依次为9,18,27,36,45,54,63,72,81 ①2.S，M，L，XL，XXL，XXXL型号的女装上对应的尺码分别是38,40,42,44,46,48 ②3.测量某地垂直地面方向上海拔500米以下的大气温度，得到从距离地面20米起每升高100米处的大气温度（单位℃）依次为25,24,23,22,21 ③
人教版高中数学选择性必修二等差数列的概念（2）教学设计
二、典例解析例3.某公司购置了一台价值为220万元的设备，随着设备在使用过程中老化，其价值会逐年减少.经验表明，每经过一年其价值会减少d(d为正常数）万元.已知这台设备的使用年限为10年，超过10年 ，它的价值将低于购进价值的5%，设备将报废.请确定d的范围.分析：该设备使用n年后的价值构成数列{an}，由题意可知，an＝an－1－d (n≥2). 即：an－an－1＝－d.所以{an}为公差为－d的等差数列.10年之内（含10年），该设备的价值不小于（220×5%=）11万元；10年后，该设备的价值需小于11万元．利用{an}的通项公式列不等式求解．解：设使用n年后，这台设备的价值为an万元，则可得数列{an}．由已知条件，得an＝an－1－d（n≥2）．所以数列{an}是一个公差为－d的等差数列.因为a1＝220－d，所以an＝220－d＋(n－1)(－d)＝220－nd. 由题意，得a10≥11，a11＜11. 即：{█("220－10d≥11" @"220－11d＜11" )┤解得19<d≤20.9所以，d的求值范围为19<d≤20.9
人教版高中数学选择性必修二数列的概念（1）教学设计
情景导学古语云:“勤学如春起之苗,不见其增,日有所长”如果对“春起之苗”每日用精密仪器度量,则每日的高度值按日期排在一起,可组成一个数列. 那么什么叫数列呢?二、问题探究1. 王芳从一岁到17岁，每年生日那天测量身高，将这些身高数据（单位：厘米）依次排成一列数：75,87,96,103,110,116,120,128,138，145,153,158,160,162,163,165,168 ①记王芳第i岁的身高为 h_i ，那么h_1=75 , h_2=87, 〖"…" ，h〗_17=168.我们发现h_i中的i反映了身高按岁数从1到17的顺序排列时的确定位置，即h_1=75 是排在第1位的数，h_2=87是排在第2位的数〖"…" ，h〗_17 =168是排在第17位的数，它们之间不能交换位置，所以①具有确定顺序的一列数。2. 在两河流域发掘的一块泥板（编号K90，约生产于公元前7世纪）上，有一列依次表示一个月中从第1天到第15天，每天月亮可见部分的数：5,10,20,40,80,96,112,128,144,160,176,192,208,224,240. ②
人教版高中数学选修3离散型随机变量及其分布列(1)教学设计
4.写出下列随机变量可能取的值，并说明随机变量所取的值表示的随机试验的结果．(1)一个袋中装有8个红球，3个白球，从中任取5个球，其中所含白球的个数为X.(2)一个袋中有5个同样大小的黑球，编号为1,2,3,4,5，从中任取3个球，取出的球的最大号码记为X.(3). 在本例(1)条件下，规定取出一个红球赢2元，而每取出一个白球输1元，以ξ表示赢得的钱数，结果如何？[解] (1)X可取0,1,2,3.X＝0表示取5个球全是红球；X＝1表示取1个白球，4个红球；X＝2表示取2个白球，3个红球；X＝3表示取3个白球，2个红球．(2)X可取3,4,5.X＝3表示取出的球编号为1,2,3；X＝4表示取出的球编号为1,2,4；1,3,4或2,3,4.X＝5表示取出的球编号为1,2,5；1,3,5；1,4,5；2,3,5；2,4,5或3,4,5.(3) ξ＝10表示取5个球全是红球；ξ＝7表示取1个白球，4个红球；ξ＝4表示取2个白球，3个红球；ξ＝1表示取3个白球，2个红球．
人教版高中数学选修3离散型随机变量的方差教学设计
3.下结论.依据均值和方差做出结论.跟踪训练2. A、B两个投资项目的利润率分别为随机变量X1和X2，根据市场分析， X1和X2的分布列分别为X1 2% 8% 12% X2 5% 10%P 0.2 0.5 0.3 P 0.8 0.2求：(1)在A、B两个项目上各投资100万元， Y1和Y2分别表示投资项目A和B所获得的利润，求方差D(Y1)和D(Y2)；(2)根据得到的结论，对于投资者有什么建议？ 解：(1)题目可知，投资项目A和B所获得的利润Y1和Y2的分布列为：Y1 2 8 12 Y2 5 10P 0.2 0.5 0.3 P 0.8 0.2所以 ;; 解：(2) 由(1)可知 ，说明投资A项目比投资B项目期望收益要高；同时 ，说明投资A项目比投资B项目的实际收益相对于期望收益的平均波动要更大.因此，对于追求稳定的投资者，投资B项目更合适;而对于更看重利润并且愿意为了高利润承担风险的投资者，投资A项目更合适.
人教版高中数学选择性必修二函数的单调性(1) 教学设计
1．判断正误(正确的打“√”，错误的打“×”)(1)函数f (x)在区间(a，b)上都有f ′(x)＜0，则函数f (x)在这个区间上单调递减． ( )(2)函数在某一点的导数越大，函数在该点处的切线越“陡峭”． ( )(3)函数在某个区间上变化越快，函数在这个区间上导数的绝对值越大．( )(4)判断函数单调性时，在区间内的个别点f ′(x)＝0，不影响函数在此区间的单调性．( )[解析] (1)√ 函数f (x)在区间(a，b)上都有f ′(x)＜0，所以函数f (x)在这个区间上单调递减，故正确．(2)× 切线的“陡峭”程度与|f ′(x)|的大小有关，故错误．(3)√ 函数在某个区间上变化的快慢，和函数导数的绝对值大小一致．(4)√ 若f ′(x)≥0(≤0)，则函数f (x)在区间内单调递增(减)，故f ′(x)＝0不影响函数单调性．[答案] (1)√ (2)× (3)√ (4)√例1. 利用导数判断下列函数的单调性:（1）f(x)=x^3+3x; （2） f(x)=sinx-x,x∈(0,π); (3)f(x)=(x-1)/x解: (1) 因为f(x)=x^3+3x, 所以f^' (x)=〖3x〗^2+3=3(x^2+1)>0所以f(x)=x^3+3x ，函数在R上单调递增，如图（1）所示
人教版高中数学选修3分类变量与列联表教学设计
一、 问题导学前面两节所讨论的变量,如人的身高、树的胸径、树的高度、短跑100m世界纪录和创纪录的时间等,都是数值变量,数值变量的取值为实数.其大小和运算都有实际含义.在现实生活中,人们经常需要回答一定范围内的两种现象或性质之间是否存在关联性或相互影响的问题.例如,就读不同学校是否对学生的成绩有影响,不同班级学生用于体育锻炼的时间是否有差别,吸烟是否会增加患肺癌的风险,等等,本节将要学习的独立性检验方法为我们提供了解决这类问题的方案。在讨论上述问题时,为了表述方便,我们经常会使用一种特殊的随机变量,以区别不同的现象或性质,这类随机变量称为分类变量.分类变量的取值可以用实数表示,例如,学生所在的班级可以用1,2,3等表示,男性、女性可以用1,0表示,等等.在很多时候,这些数值只作为编号使用,并没有通常的大小和运算意义,本节我们主要讨论取值于{0,1}的分类变量的关联性问题.
人教版高中数学选修3二项式系数的性质教学设计
1.对称性与首末两端“等距离”的两个二项式系数相等,即C_n^m=C_n^(n"-" m).2.增减性与最大值 当k(n+1)/2时,C_n^k随k的增加而减小.当n是偶数时,中间的一项C_n^(n/2)取得最大值;当n是奇数时,中间的两项C_n^((n"-" 1)/2) 与C_n^((n+1)/2)相等,且同时取得最大值.探究2.已知(1+x)^n =C_n^0+C_n^1 x+...〖+C〗_n^k x^k+...+C_n^n x^n 3.各二项式系数的和C_n^0+C_n^1+C_n^2+…+C_n^n=2n.令x=1 得(1+1)^n=C_n^0+C_n^1 +...+C_n^n=2^n所以，(a+b)^n 的展开式的各二项式系数之和为2^n1. 在(a+b)8的展开式中,二项式系数最大的项为 ,在(a+b)9的展开式中,二项式系数最大的项为 . 解析:因为(a+b)8的展开式中有9项,所以中间一项的二项式系数最大,该项为C_8^4a4b4=70a4b4.因为(a+b)9的展开式中有10项,所以中间两项的二项式系数最大,这两项分别为C_9^4a5b4=126a5b4,C_9^5a4b5=126a4b5.答案:1.70a4b4 126a5b4与126a4b5 2. A=C_n^0+C_n^2+C_n^4+…与B=C_n^1+C_n^3+C_n^5+…的大小关系是( )A.A>B B.A=B C.A<B D.不确定 解析:∵(1+1)n=C_n^0+C_n^1+C_n^2+…+C_n^n=2n,(1-1)n=C_n^0-C_n^1+C_n^2-…+(-1)nC_n^n=0,∴C_n^0+C_n^2+C_n^4+…=C_n^1+C_n^3+C_n^5+…=2n-1,即A=B.答案:B
人教版高中数学选修3一元线性回归模型及其应用教学设计
1.确定研究对象，明确哪个是解释变量，哪个是响应变量；2.由经验确定非线性经验回归方程的模型；3.通过变换，将非线性经验回归模型转化为线性经验回归模型；4.按照公式计算经验回归方程中的参数，得到经验回归方程；5.消去新元，得到非线性经验回归方程；6.得出结果后分析残差图是否有异常 ．跟踪训练1.一只药用昆虫的产卵数y与一定范围内的温度x有关，现收集了6组观测数据列于表中： 经计算得： 线性回归残差的平方和: ∑_(i=1)^6?〖(y_i-(y_i ) ?)〗^2=236,64,e^8.0605≈3167.其中 分别为观测数据中的温度和产卵数，i=1,2,3,4,5,6.(1)若用线性回归模型拟合，求y关于x的回归方程 (精确到0.1）；(2)若用非线性回归模型拟合，求得y关于x回归方程为 且相关指数R2＝0.9522． ①试与(1)中的线性回归模型相比较，用R2说明哪种模型的拟合效果更好 ?②用拟合效果好的模型预测温度为35℃时该种药用昆虫的产卵数.(结果取整数).
新人教版高中英语必修3Unit 1 Festivals and Celebrations-Listening &Speaking＆Talking教学设计
The theme of this section is “Talk about festival activities and festival experiences”.Festival and holiday is a relaxing and interesting topic for students. This part talks about the topic from the daily life of students’. In the part A ---Listening and Speaking, there are three conversations among different speakers from three countries(Japan, Rio and China), where the speakers are participating in or going to participate in the festivals and celebrations. So listening for the relationship among them is a fundamental task. Actually, with the globalization and more international communication, it is normal for Chinese or foreigners to witness different festivals and celebrations in or out of China. In the Conversation 1, a foreign reporter is interviewing a Japanese young girl who just had participated in the ceremony of the Coming-of-Age Day on the street and asking her feeling about the ceremony and the afterwards activities. Conversation 2, Chinese girl Li Mei is witnessing the Rio Carnival for the first time, and her friend Carla gives her some advice on the costumes which enables her to match with the carnival to have a good time. Conversation 3, a Chinese guide is showing a group of foreign visitors around the Lantern Festival and introducing the customs of the festival to them. The three conversations have a strong vitality and insert the festival and cultural elements from different countries. So perceiving the festivals and cultures from different countries is the second task. At the same time, the scripts also insert the targeted grammar --- v-ing as attributive and predicative, which students can perceive and experience in a real context and make a road for the further study. That is the third task. In the Part B--- Listening and Talking, the theme is “Talk about festival experience”, which is the common topic in our daily conversations. During the conversation, Song Lin, a Chinese student, asked Canadian friend Max about how to spend Christmas. In the conversation, Song Lin talked about experience and the feelings during the Chinese Spring Festival, during which there are not only some enjoyable things but some unpleasant things. After the listening, perhaps students find there are some similarities between Christmas and the Chinese Spring Festival as there are some differences in the origins and celebrations. For example, people always visit friends and relatives, decorate their houses, have a big dinner together, chat and give presents to each other.
