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人教版新课标小学数学五年级上册简易方程说课稿

  • 新人教版高中英语选修2Unit 1 Science and Scientists-Learning about Language教学设计

    新人教版高中英语选修2Unit 1 Science and Scientists-Learning about Language教学设计

    Step 7: complete the discourse according to the grammar rules.Cholera used to be one of the most 1.__________ (fear) diseases in the world. In the early 19th century, _2_________ an outbreak of cholera hit Europe, millions of people died. But neither its cause, 3__________ its cure was understood. A British doctor, John Snow, wanted to solve the problem and he knew that cholera would not be controlled _4_________ its cause was found. In general, there were two contradictory theories 5 __________ explained how cholera spread. The first suggested that bad air caused the disease. The second was that cholera was caused by an _6_________(infect) from germs in food or water. John Snow thought that the second theory was correct but he needed proof. So when another outbreak of cholera hit London in 1854, he began to investigate. Later, with all the evidence he _7_________ (gather), John Snow was able to announce that the pump water carried cholera germs. Therefore, he had the handle of the pump _8_________ (remove) so that it couldn't be used. Through his intervention,the disease was stopped in its tracks. What is more, John Snow found that some companies sold water from the River Thames that __9__________________ (pollute) by raw waste. The people who drank this water were much more likely _10_________ (get) cholera than those who drank pure or boiled water. Through John Snow's efforts, the _11_________ (threaten) of cholera around the world saw a substantial increase. Keys: 1.feared 2.when 3. nor 4.unless 5.that/which 6.infection 7.had gathered 8.removed 9.was polluted 10.to get 11. threat

  • 新人教版高中英语选修2Unit 1 Science and Scientists-Reading and thinking教学设计

    新人教版高中英语选修2Unit 1 Science and Scientists-Reading and thinking教学设计

    Step 5: After learning the text, discuss with your peers about the following questions:1.John Snow believed Idea 2 was right. How did he finally prove it?2. Do you think John Snow would have solved this problem without the map?3. Cholera is a 19th century disease. What disease do you think is similar to cholera today?SARS and Covid-19 because they are both deadly and fatally infectious, have an unknown cause and need serious public health care to solve them urgently.keys:1. John Snow finally proved his idea because he found an outbreak that was clearly related to cholera, collected information and was able to tie cases outside the area to the polluted water.2. No. The map helped John Snow organize his ideas. He was able to identify those households that had had many deaths and check their water-drinking habits. He identified those houses that had had no deaths and surveyed their drinking habits. The evidence clearly pointed to the polluted water being the cause.3. SARS and Covid-19 because they are both deadly and fatally infectious, have an unknown cause and need serious public health care to solve them urgently.Step 6: Consolidate what you have learned by filling in the blanks:John Snow was a well-known _1___ in London in the _2__ century. He wanted to find the _3_____ of cholera in order to help people ___4_____ it. In 1854 when a cholera __5__ London, he began to gather information. He ___6__ on a map ___7___ all the dead people had lived and he found that many people who had ___8____ (drink) the dirty water from the __9____ died. So he decided that the polluted water ___10____ cholera. He suggested that the ___11__ of all water supplies should be _12______ and new methods of dealing with ____13___ water be found. Finally, “King Cholera” was __14_____.Keys: 1. doctor 2. 19th 3.cause 4.infected with 5.hit 6.marked 7.where 8.drunk 9.pump 10.carried 11.source 12.examined 13.polluted 14.defeatedHomework: Retell the text after class and preview its language points

  • 新人教版高中英语选修2Unit 1 Science and Scientists-Using langauge教学设计

    新人教版高中英语选修2Unit 1 Science and Scientists-Using langauge教学设计

    This happens because the dish soap molecules have a strong negative charge, and the milk molecules have a strong positive charge. Like magnets, these molecules are attracted to each other, and so they appear to move around on the plate, taking the food coloring with them, making it look like the colors are quickly moving to escape from the soap.Listening text:? Judy: Oh, I'm so sorry that you were ill and couldn't come with us on our field trip. How are you feeling now? Better?? Bill: Much better, thanks. But how was it?? Judy: Wonderful! I especially liked an area of the museum called Light Games.it was really cool. They had a hall of mirrors where I could see myself reflected thousands of times!? Bill: A hall of mirrors can be a lot of fun. What else did they have?? Judy: Well, they had an experiment where we looked at a blue screen for a while, and then suddenly we could see tiny bright lights moving around on it. You'll never guess what those bright lights were!? Bill: Come on, tell me!? Judy: They were our own blood cells. For some reason, our eyes play tricks on us when we look at a blue screen, and we can see our own blood cells moving around like little lights! But there was another thing I liked better. I stood in front of a white light, and it cast different shadows of me in every color of the rainbow!? Bill: Oh, I wish I had been there. Tell me more!? Judy: Well, they had another area for sound. They had a giant piano keyboard that you could use your feet to play. But then, instead of playing the sounds of a piano, it played the voices of classical singers! Then they had a giant dish, and when you spoke into it, it reflected the sound back and made it louder. You could use it to speak in a whisper to someone 17 meters away.? Bill: It all sounds so cool. I wish I could have gone with you? Judy: I know, but we can go together this weekend. I'd love to go there again!? Bill: That sounds like a great idea!

  • 新人教版高中英语选修2Unit 2 Bridging Cultures-Discovering useful structures教学设计

    新人教版高中英语选修2Unit 2 Bridging Cultures-Discovering useful structures教学设计

    The grammar of this unit is designed to review noun clauses. Sentences that use nouns in a sentence are called noun clauses. Nominal clauses can act as subject, object, predicate, appositive and other components in compound sentences. According to the above-mentioned different grammatical functions, nominal clauses are divided into subject clause, object clause, predicate clause and appositive clause. In this unit, we will review the three kinds of nominal clauses. Appositive clauses are not required to be mastered in the optional compulsory stage, so they are not involved.1. Guide the students to judge the compound sentences and determine the composition of the clauses in the sentence.2. Instruct students to try to learn grammar by generalizing grammar rules, controlling written practice, and semi-open oral output.3. Inspire the students to systematize the function and usage of noun clause1.Instruct students to try to learn grammar by generalizing grammar rules, controlling written practice, and semi-open oral output.2.Inspire the students to systematize the function and usage of noun clauseStep1: The teacher ask studetns to find out more nominal clauses from the reading passage and udnerline the nominal clauses.

  • 新人教版高中英语选修2Unit 3 Food and Culture-Discovering useful structures教学设计

    新人教版高中英语选修2Unit 3 Food and Culture-Discovering useful structures教学设计

    The newspaper reported more than 100 people had been killed in the thunderstorm.报纸报道说有一百多人在暴风雨中丧生。(2)before、when、by the time、until、after、once等引导的时间状语从句的谓语是一般过去时,以及by、before后面接过去的时间时,主句动作发生在从句的动作或过去的时间之前且表示被动时,要用过去完成时的被动语态。By the time my brother was 10, he had been sent to Italy.我弟弟10岁前就已经被送到意大利了。Tons of rice had been produced by the end of last month. 到上月底已生产了好几吨大米。(3) It was the first/second/last ... time that ...句中that引导的定语从句中,主语与谓语构成被动关系时,要用过去完成时的被动语态。It was the first time that I had seen the night fact to face in one and a half years. 这是我一年半以来第一次亲眼目睹夜晚的景色。(4)在虚拟语气中,条件句表示与过去事实相反,且主语与谓语构成被动关系时,要用过去完成时的被动语态。If I had been instructed by him earlier, I would have finished the task.如果我早一点得到他的指示,我早就完成这项任务了。If I had hurried, I wouldn't have missed the train.如果我快点的话,我就不会误了火车。If you had been at the party, you would have met him. 如果你去了晚会,你就会见到他的。

  • 新人教版高中英语选修2Unit 3 Food and Culture-Reading and thinking教学设计

    新人教版高中英语选修2Unit 3 Food and Culture-Reading and thinking教学设计

    The discourse explores the link between food and culture from a foreign’s perspective and it records some authentic Chinese food and illustrates the cultural meaning, gerography features and historic tradition that the food reflects. It is aimed to lead students to understand and think about the connection between food and culture. While teaching, the teacher should instruct students to find out the writing order and the writer’s experieces and feelings towards Chinese food and culture.1.Guide the students to read the text, sort out the information and dig out the topic.2.Understand the cultural connotation, regional characteristics and historical tradition of Chinese cuisine3.Understand and explore the relationship between food and people's personality4.Guide the students to use the cohesive words in the text5.Lead students to accurately grasp the real meaning of the information and improve the overall understanding ability by understanding the implied meaning behind the text.1. Enable the Ss to understand the structure and the writing style of the passage well.2. Lead the Ss to understand and think further about the connection between food and geography and local character traits.Step1: Prediction before reading. Before you read, look at the title, and the picture. What do you think this article is about?keys:It is about various culture and cuisine about a place or some countries.

  • 新人教版高中英语选修2Unit 5 First Aid-Discovering useful structures教学设计

    新人教版高中英语选修2Unit 5 First Aid-Discovering useful structures教学设计

    You have no excuse for not going.你没有理由不去。He was punished for not having finished his homework.他因未完成作业而受到惩罚。2.动词­ing形式复合结构由物主代词或人称代词宾格、名词所有格或普通格加动词­ing,即“sb./sb.'s+doing”构成。动词­ing形式的复合结构实际上是给动词­ing形式加了一个逻辑主语。动词­ing形式的复合结构有四种形式:①形容词性物主代词+动词­ing②名词所有格+动词­ing③代词宾格+动词­ing④名词+动词­ingHer coming to help encouraged all of us.她来帮忙鼓舞了我们所有人。The baby was made awake by the door suddenly shutting.这个婴儿被突然的关门声吵醒了。Can you imagine him/Jack cooking at home?你能想象他/杰克在家做饭的样子吗?无生命名词无论是作主语还是作宾语都不能用第②种形式。Tom's winning first prize last year impressed me a lot.汤姆去年得了一等奖使我印象深刻。Do you mind my/me/Jack's/Jack leaving now?你介意我/杰克现在离开吗?Excuse me for my not coming on time.很抱歉我没能按时来。His father's being ill made him worried.他父亲病了,他很担心。We are looking forward to the singer's/the singer to give us a concert.我们盼望着这位歌手来给我们举办一场演唱会。

  • 教学反思数学仿编应用题活动《小鬼当家》课件教案

    教学反思数学仿编应用题活动《小鬼当家》课件教案

    目的:1、让幼儿学会仿编和解答4的加减应用题。2、在生活情景中能根据水果卡片自编4的加减应用题。准备:1、知识经验准备:请家长带 幼儿去买东西,使幼儿了解一个买与卖的过程。2、物质准备:准备各种水果卡片,人手4个替代物作钱。过程:一、以“帮农民伯伯摘果子”引入。“小朋友,果园里的水果都成熟了,农民伯伯想请你们帮他摘水果,你们愿意吗?”(愿意)二、游戏“摘水果”。师交代游戏玩法和规则。三、分类活动:分水果。1、引导幼儿将自己所摘的水果跟同伴之间进行交流。2、交代任务:将各种水果分别放在筐里。

  • 空间向量基本定理教学设计人教A版高中数学选择性必修第一册

    空间向量基本定理教学设计人教A版高中数学选择性必修第一册

    反思感悟用基底表示空间向量的解题策略1.空间中,任一向量都可以用一个基底表示,且只要基底确定,则表示形式是唯一的.2.用基底表示空间向量时,一般要结合图形,运用向量加法、减法的平行四边形法则、三角形法则,以及数乘向量的运算法则,逐步向基向量过渡,直至全部用基向量表示.3.在空间几何体中选择基底时,通常选取公共起点最集中的向量或关系最明确的向量作为基底,例如,在正方体、长方体、平行六面体、四面体中,一般选用从同一顶点出发的三条棱所对应的向量作为基底.例2.在棱长为2的正方体ABCD-A1B1C1D1中,E,F分别是DD1,BD的中点,点G在棱CD上,且CG=1/3 CD(1)证明:EF⊥B1C;(2)求EF与C1G所成角的余弦值.思路分析选择一个空间基底,将(EF) ?,(B_1 C) ?,(C_1 G) ?用基向量表示.(1)证明(EF) ?·(B_1 C) ?=0即可;(2)求(EF) ?与(C_1 G) ?夹角的余弦值即可.(1)证明:设(DA) ?=i,(DC) ?=j,(DD_1 ) ?=k,则{i,j,k}构成空间的一个正交基底.

  • 点到直线的距离公式教学设计人教A版高中数学选择性必修第一册

    点到直线的距离公式教学设计人教A版高中数学选择性必修第一册

    4.已知△ABC三个顶点坐标A(-1,3),B(-3,0),C(1,2),求△ABC的面积S.【解析】由直线方程的两点式得直线BC的方程为 = ,即x-2y+3=0,由两点间距离公式得|BC|= ,点A到BC的距离为d,即为BC边上的高,d= ,所以S= |BC|·d= ×2 × =4,即△ABC的面积为4.5.已知直线l经过点P(0,2),且A(1,1),B(-3,1)两点到直线l的距离相等,求直线l的方程.解:(方法一)∵点A(1,1)与B(-3,1)到y轴的距离不相等,∴直线l的斜率存在,设为k.又直线l在y轴上的截距为2,则直线l的方程为y=kx+2,即kx-y+2=0.由点A(1,1)与B(-3,1)到直线l的距离相等,∴直线l的方程是y=2或x-y+2=0.得("|" k"-" 1+2"|" )/√(k^2+1)=("|-" 3k"-" 1+2"|" )/√(k^2+1),解得k=0或k=1.(方法二)当直线l过线段AB的中点时,A,B两点到直线l的距离相等.∵AB的中点是(-1,1),又直线l过点P(0,2),∴直线l的方程是x-y+2=0.当直线l∥AB时,A,B两点到直线l的距离相等.∵直线AB的斜率为0,∴直线l的斜率为0,∴直线l的方程为y=2.综上所述,满足条件的直线l的方程是x-y+2=0或y=2.

  • 两点间的距离公式教学设计人教A版高中数学选择性必修第一册

    两点间的距离公式教学设计人教A版高中数学选择性必修第一册

    一、情境导学在一条笔直的公路同侧有两个大型小区,现在计划在公路上某处建一个公交站点C,以方便居住在两个小区住户的出行.如何选址能使站点到两个小区的距离之和最小?二、探究新知问题1.在数轴上已知两点A、B,如何求A、B两点间的距离?提示:|AB|=|xA-xB|.问题2:在平面直角坐标系中能否利用数轴上两点间的距离求出任意两点间距离?探究.当x1≠x2,y1≠y2时,|P1P2|=?请简单说明理由.提示:可以,构造直角三角形利用勾股定理求解.答案:如图,在Rt △P1QP2中,|P1P2|2=|P1Q|2+|QP2|2,所以|P1P2|=?x2-x1?2+?y2-y1?2.即两点P1(x1,y1),P2(x2,y2)间的距离|P1P2|=?x2-x1?2+?y2-y1?2.你还能用其它方法证明这个公式吗?2.两点间距离公式的理解(1)此公式与两点的先后顺序无关,也就是说公式也可写成|P1P2|=?x2-x1?2+?y2-y1?2.(2)当直线P1P2平行于x轴时,|P1P2|=|x2-x1|.当直线P1P2平行于y轴时,|P1P2|=|y2-y1|.

  • 倾斜角与斜率教学设计人教A版高中数学选择性必修第一册

    倾斜角与斜率教学设计人教A版高中数学选择性必修第一册

    (2)l的倾斜角为90°,即l平行于y轴,所以m+1=2m,得m=1.延伸探究1 本例条件不变,试求直线l的倾斜角为锐角时实数m的取值范围.解:由题意知(m"-" 1"-" 1)/(m+1"-" 2m)>0,解得1<m<2.延伸探究2 若将本例中的“N(2m,1)”改为“N(3m,2m)”,其他条件不变,结果如何?解:(1)由题意知(m"-" 1"-" 2m)/(m+1"-" 3m)=1,解得m=2.(2)由题意知m+1=3m,解得m=1/2.直线斜率的计算方法(1)判断两点的横坐标是否相等,若相等,则直线的斜率不存在.(2)若两点的横坐标不相等,则可以用斜率公式k=(y_2 "-" y_1)/(x_2 "-" x_1 )(其中x1≠x2)进行计算.金题典例 光线从点A(2,1)射到y轴上的点Q,经y轴反射后过点B(4,3),试求点Q的坐标及入射光线的斜率.解:(方法1)设Q(0,y),则由题意得kQA=-kQB.∵kQA=(1"-" y)/2,kQB=(3"-" y)/4,∴(1"-" y)/2=-(3"-" y)/4.解得y=5/3,即点Q的坐标为 0,5/3 ,∴k入=kQA=(1"-" y)/2=-1/3.(方法2)设Q(0,y),如图,点B(4,3)关于y轴的对称点为B'(-4,3), kAB'=(1"-" 3)/(2+4)=-1/3,由题意得,A、Q、B'三点共线.从而入射光线的斜率为kAQ=kAB'=-1/3.所以,有(1"-" y)/2=(1"-" 3)/(2+4),解得y=5/3,点Q的坐标为(0,5/3).

  • 直线与圆的位置关系教学设计人教A版高中数学选择性必修第一册

    直线与圆的位置关系教学设计人教A版高中数学选择性必修第一册

    切线方程的求法1.求过圆上一点P(x0,y0)的圆的切线方程:先求切点与圆心连线的斜率k,则由垂直关系,切线斜率为-1/k,由点斜式方程可求得切线方程.若k=0或斜率不存在,则由图形可直接得切线方程为y=b或x=a.2.求过圆外一点P(x0,y0)的圆的切线时,常用几何方法求解设切线方程为y-y0=k(x-x0),即kx-y-kx0+y0=0,由圆心到直线的距离等于半径,可求得k,进而切线方程即可求出.但要注意,此时的切线有两条,若求出的k值只有一个时,则另一条切线的斜率一定不存在,可通过数形结合求出.例3 求直线l:3x+y-6=0被圆C:x2+y2-2y-4=0截得的弦长.思路分析:解法一求出直线与圆的交点坐标,解法二利用弦长公式,解法三利用几何法作出直角三角形,三种解法都可求得弦长.解法一由{■(3x+y"-" 6=0"," @x^2+y^2 "-" 2y"-" 4=0"," )┤得交点A(1,3),B(2,0),故弦AB的长为|AB|=√("(" 2"-" 1")" ^2+"(" 0"-" 3")" ^2 )=√10.解法二由{■(3x+y"-" 6=0"," @x^2+y^2 "-" 2y"-" 4=0"," )┤消去y,得x2-3x+2=0.设两交点A,B的坐标分别为A(x1,y1),B(x2,y2),则由根与系数的关系,得x1+x2=3,x1·x2=2.∴|AB|=√("(" x_2 "-" x_1 ")" ^2+"(" y_2 "-" y_1 ")" ^2 )=√(10"[(" x_1+x_2 ")" ^2 "-" 4x_1 x_2 "]" ┴" " )=√(10×"(" 3^2 "-" 4×2")" )=√10,即弦AB的长为√10.解法三圆C:x2+y2-2y-4=0可化为x2+(y-1)2=5,其圆心坐标(0,1),半径r=√5,点(0,1)到直线l的距离为d=("|" 3×0+1"-" 6"|" )/√(3^2+1^2 )=√10/2,所以半弦长为("|" AB"|" )/2=√(r^2 "-" d^2 )=√("(" √5 ")" ^2 "-" (√10/2) ^2 )=√10/2,所以弦长|AB|=√10.

  • 两条平行线间的距离教学设计人教A版高中数学选择性必修第一册

    两条平行线间的距离教学设计人教A版高中数学选择性必修第一册

    一、情境导学前面我们已经得到了两点间的距离公式,点到直线的距离公式,关于平面上的距离问题,两条直线间的距离也是值得研究的。思考1:立定跳远测量的什么距离?A.两平行线的距离 B.点到直线的距离 C. 点到点的距离二、探究新知思考2:已知两条平行直线l_1,l_2的方程,如何求l_1 〖与l〗_2间的距离?根据两条平行直线间距离的含义,在直线l_1上取任一点P(x_0,y_0 ),,点P(x_0,y_0 )到直线l_2的距离就是直线l_1与直线l_2间的距离,这样求两条平行线间的距离就转化为求点到直线的距离。两条平行直线间的距离1. 定义:夹在两平行线间的__________的长.公垂线段2. 图示: 3. 求法:转化为点到直线的距离.1.原点到直线x+2y-5=0的距离是( )A.2 B.3 C.2 D.5D [d=|-5|12+22=5.选D.]

  • 圆与圆的位置关系教学设计人教A版高中数学选择性必修第一册

    圆与圆的位置关系教学设计人教A版高中数学选择性必修第一册

    1.两圆x2+y2-1=0和x2+y2-4x+2y-4=0的位置关系是( )A.内切 B.相交 C.外切 D.外离解析:圆x2+y2-1=0表示以O1(0,0)点为圆心,以R1=1为半径的圆.圆x2+y2-4x+2y-4=0表示以O2(2,-1)点为圆心,以R2=3为半径的圆.∵|O1O2|=√5,∴R2-R1<|O1O2|<R2+R1,∴圆x2+y2-1=0和圆x2+y2-4x+2y-4=0相交.答案:B2.圆C1:x2+y2-12x-2y-13=0和圆C2:x2+y2+12x+16y-25=0的公共弦所在的直线方程是 . 解析:两圆的方程相减得公共弦所在的直线方程为4x+3y-2=0.答案:4x+3y-2=03.半径为6的圆与x轴相切,且与圆x2+(y-3)2=1内切,则此圆的方程为( )A.(x-4)2+(y-6)2=16 B.(x±4)2+(y-6)2=16C.(x-4)2+(y-6)2=36 D.(x±4)2+(y-6)2=36解析:设所求圆心坐标为(a,b),则|b|=6.由题意,得a2+(b-3)2=(6-1)2=25.若b=6,则a=±4;若b=-6,则a无解.故所求圆方程为(x±4)2+(y-6)2=36.答案:D4.若圆C1:x2+y2=4与圆C2:x2+y2-2ax+a2-1=0内切,则a等于 . 解析:圆C1的圆心C1(0,0),半径r1=2.圆C2可化为(x-a)2+y2=1,即圆心C2(a,0),半径r2=1,若两圆内切,需|C1C2|=√(a^2+0^2 )=2-1=1.解得a=±1. 答案:±1 5. 已知两个圆C1:x2+y2=4,C2:x2+y2-2x-4y+4=0,直线l:x+2y=0,求经过C1和C2的交点且和l相切的圆的方程.解:设所求圆的方程为x2+y2+4-2x-4y+λ(x2+y2-4)=0,即(1+λ)x2+(1+λ)y2-2x-4y+4(1-λ)=0.所以圆心为 1/(1+λ),2/(1+λ) ,半径为1/2 √((("-" 2)/(1+λ)) ^2+(("-" 4)/(1+λ)) ^2 "-" 16((1"-" λ)/(1+λ))),即|1/(1+λ)+4/(1+λ)|/√5=1/2 √((4+16"-" 16"(" 1"-" λ^2 ")" )/("(" 1+λ")" ^2 )).解得λ=±1,舍去λ=-1,圆x2+y2=4显然不符合题意,故所求圆的方程为x2+y2-x-2y=0.

  • 人教版高中政治必修4第十课创新意识与社会进步教案

    人教版高中政治必修4第十课创新意识与社会进步教案

    2.辩证的否定(1)辩证的否定是事物的自我否定。事物内部存在着肯定方面和否定方面,它们既对立又统一。最初,肯定方面处于支配地位,否定方面处于被支配地位。在这种情况下,事物就被肯定着。但是,在矛盾双方的斗争中,否定方面总会由弱变强。一旦否定方面由被支配地位上升为支配地位,事物就转化到了自己的对立面,实现了对事物的否定。事物最终之所以被否定,根源在于事物的内部,是事物内部的否定因素战胜了肯定因素。因此,事物的否定是自我否定。(2)辩证的否定是事物发展的环节和联系的环节。所谓发展,是指新事物的产生和旧事物的灭亡。而实现这一过程必须要对旧事物进行否定,否定实现了事物由旧质向新质的飞跃。新事物在否定旧事物时,并不是把旧事物全盘抛弃,一笔勾销。旧事物是新事物的母体,新事物从旧事物那里脱胎而来,新事物是在批判地继承旧事物中的一切积极的有生命力的因素的基础上发展起来的。这样,在新旧事物之间就存在着必然的联系。

  • 人教版高中政治必修4第十课创新意识与社会进步精品教案

    人教版高中政治必修4第十课创新意识与社会进步精品教案

    在数学上,0这个数是解决记数和进位问题而引进的概念,由于它不能表示实在的东西,很长时间人们不把它看作是一个数。认为0是无,是对有的否定。从唯物辩证法的观点看,这种否定不是形而上学的简单否定,而是具有丰富内容的辨证否定。辨证的否定是发展的环节。0是从无到有的必经之路,是连接无和有的桥梁。0又是正数和负数之间的界限,它既否定了任何正数,也否定了任何负数,是唯一的中性数。但它又是联结正数和负数的中间环节。没有0,负数就过渡不到正数去,正数也休想发展到负数来。数学中的0是对任何定量的否定。如果没有这一否定,任何量的发展都无从谈起。这个否定不是一笔勾销,而是扬弃。因为它克服了任何定量的有限性,成为其发展的环节。在现实生活中,0作为辨证的否定,也体现出联系和发展的性质。如0度不是没有温度,而是非常确定的温度。

  • 新人教版高中英语必修3Unit 5 The Value of Money-Discovering Useful Structures导学案

    新人教版高中英语必修3Unit 5 The Value of Money-Discovering Useful Structures导学案

    4.They were going to find someone to take part in their bet when they saw Henry walking on the street outside.[归纳]1.过去将来时的基本构成和用法过去将来时由“would+动词原形”构成,主要表示从过去某一时间来看将要发生的动作(尤其用于宾语从句中),还可以表示过去的动作习惯或倾向。Jeff knew he would be tired the next day.He promised that he would not open the letter until 2 o'clock.She said that she wouldn't do that again.2.表示过去将来时的其他表达法(1)was/were going to+动词原形:该结构有两个主要用法,一是表示过去的打算,二是表示在过去看来有迹象表明将要发生某事。I thought it was going to rain.(2)was/were to+动词原形:主要表示过去按计划或安排要做的事情。She said she was to get married next month.(3)was/were about to+动词原形:表示在过去看来即将要发生的动作,由于本身已含有“即将”的意味,所以不再与表示具体的将来时间状语连用。I was about to go to bed when the phone rang.(4)was/were+现在分词:表示在过去看来即将发生的动作,通常可用于该结构中的动词是come,go,leave,arrive,begin,start,stop,close,open,die,join,borrow,buy等瞬间动词。Jack said he was leaving tomorrow.

  • 人教版高中数学选修3分类加法计数原理与分步乘法计数原理(1)教学设计

    人教版高中数学选修3分类加法计数原理与分步乘法计数原理(1)教学设计

    问题1. 用一个大写的英文字母或一个阿拉伯数字给教室里的一个座位编号,总共能编出多少种不同的号码?因为英文字母共有26个,阿拉伯数字共有10个,所以总共可以编出26+10=36种不同的号码.问题2.你能说说这个问题的特征吗?上述计数过程的基本环节是:(1)确定分类标准,根据问题条件分为字母号码和数字号码两类;(2)分别计算各类号码的个数;(3)各类号码的个数相加,得出所有号码的个数.你能举出一些生活中类似的例子吗?一般地,有如下分类加法计数原理:完成一件事,有两类办法. 在第1类办法中有m种不同的方法,在第2类方法中有n种不同的方法,则完成这件事共有:N= m+n种不同的方法.二、典例解析例1.在填写高考志愿时,一名高中毕业生了解到,A,B两所大学各有一些自己感兴趣的强项专业,如表,

  • 人教版高中数学选修3分类加法计数原理与分步乘法计数原理(2)教学设计

    人教版高中数学选修3分类加法计数原理与分步乘法计数原理(2)教学设计

    当A,C颜色相同时,先染P有4种方法,再染A,C有3种方法,然后染B有2种方法,最后染D也有2种方法.根据分步乘法计数原理知,共有4×3×2×2=48(种)方法;当A,C颜色不相同时,先染P有4种方法,再染A有3种方法,然后染C有2种方法,最后染B,D都有1种方法.根据分步乘法计数原理知,共有4×3×2×1×1=24(种)方法.综上,共有48+24=72(种)方法.故选B.答案:B5.某艺术小组有9人,每人至少会钢琴和小号中的一种乐器,其中7人会钢琴,3人会小号,从中选出会钢琴与会小号的各1人,有多少种不同的选法?解:由题意可知,在艺术小组9人中,有且仅有1人既会钢琴又会小号(把该人记为甲),只会钢琴的有6人,只会小号的有2人.把从中选出会钢琴与会小号各1人的方法分为两类.第1类,甲入选,另1人只需从其他8人中任选1人,故这类选法共8种;第2类,甲不入选,则会钢琴的只能从6个只会钢琴的人中选出,有6种不同的选法,会小号的也只能从只会小号的2人中选出,有2种不同的选法,所以这类选法共有6×2=12(种).因此共有8+12=20(种)不同的选法.

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