本节课是正弦函数、余弦函数图像的继续,本课是正弦曲线、余弦曲线这两种曲线的特点得出正弦函数、余弦函数的性质. 课程目标1.了解周期函数与最小正周期的意义;2.了解三角函数的周期性和奇偶性;3.会利用周期性定义和诱导公式求简单三角函数的周期;4.借助图象直观理解正、余弦函数在[0,2π]上的性质(单调性、最值、图象与x轴的交点等);5.能利用性质解决一些简单问题. 数学学科素养1.数学抽象:理解周期函数、周期、最小正周期等的含义; 2.逻辑推理: 求正弦、余弦形函数的单调区间;3.数学运算:利用性质求周期、比较大小、最值、值域及判断奇偶性.4.数学建模:让学生借助数形结合的思想,通过图像探究正、余弦函数的性质.重点:通过正弦曲线、余弦曲线这两种曲线探究正弦函数、余弦函数的性质; 难点:应用正、余弦函数的性质来求含有cosx,sinx的函数的单调性、最值、值域及对称性.
The topic of this part is “Write about your festival experience”.During the Listening and Speaking and Talking, students are just asked to say out their festival experiences such as the Spring Festival, Mid-autumn Day, but this part students will be asked to write down their own festival experiences. During the reading part, it introduces the Naadam Festival in Inner Mongolia Autonomous Region, which can give students a good example to imitate. Students not only learn the festival, but touch and feel the Inner Mongolian’s character, the spirit and cultural atmosphere, which can help students form the cultural awareness and learn to enjoy and value the diversity of Chinese culture.Concretely, the dairy tells the experience that the author spent the Naadam Festival in Inner Mongolia Autonomous Region with his/her friend. The structure is clear. In the opening paragraph, it introduces the topic of the Naadam Festival and the whole feeling. Then it introduces the items of the festival like the ceremony, wrestling and horse racing. Finally, it summarizes this experience. Because this part is a travel journal, we must guide students pay more attention to these details: 1. use the first person. 2. use the past tense to tell the past thing and use the present or future tense to describe the scenery. 3. use the timeline to tell the development. 4. be careful for the author’s psychology, emotion and feeling, etc.1. Read quickly to get main idea; read carefully to get the detailed information about Naadam Festival.2. Learn the structure of the reading article and language.3. Write an article about a festival experience4. Learn to use the psychology, emotions and feeling in the writing.1. Write an article about a festival experience.2. Use the structure of the reading article and language.
Q4: What is the function of the International exploration ?Having astronauts from different countries on boardQ5: What can you learn from Para 4 ?China has made great achievements in exploring spaceQ6: What is the attitude to the space exploration ?SupportiveStep 6 Post reading---RetellPeople have always wanted to learn more about space. Before the mid-20th century, most people felt (1)_________ (travel) into space was an impossible dream. However, (2)____ the help of scientists, peoplesucceeded in realizing their dream (3) _________ (explore) space. On 4 October 1957, the Sputnik 1 satellite (4) ____________(launch) by the USSR. (5) ________________ scientists try to make sure nothing goes wrong, accidents can still happen. These disasters made everyone(6)___________(disappoint), but people still believe in the importance of (7) ________(carry) on space exploration. In 2003, China became the third country to (8)_____________ (independent) send humans into space. Then Shenzhou 6 and 7 completed (9)____ second manned orbit and the first Chinese spacewalk. In spite of the difficulties, scientists hope future (10)__________ (discovery) will not only enable us to understand the universe but also help us survive well into the future.Answers: 1. travelling 2. with 3. to explore 4. was launched 5. Although6. disappointed 7. carrying 8. independently 9. a 10. discoveriesStep 6 Post reading---Critical thinkingQ1: What do you think of the space exploration ? I think it is beneficial to us. Through further study of space, people will make full use of it in the future, such as the space experiments by Wang Yaping in Tian Gong 1.Q2: If you are determined to be an astronaut, what should you prepare at present ?First of all, I should study hard to get a related college degree. Besides, I must keep mental and physical healthy.Step 7. HomeworkTry to summarize the structure of the article by a mind map.
【参考范文】Narrator:(Henry is smiling as he leaves the restaurant. As he is walking down the street, he sees a sign for a place that cuts hair. He decides to get it cut. )H=Henry;B=Barber;R=rude manH:Good afternoon, I'd like to get a cut, if I may. (The barber looks at Henry's hair and continues cutting another man's hair. )Er, I'd really like a haircut. As you can see it's much too long. B:(in a rude manner) Yes, I can see that. Indeed, I can. H:Fine, well I'll have a seat then. (He sits in one of the barber's chairs. The barber turns to look at Henry. )B:It's quite expensive here, you know!Are you sure you can afford it?H:Yes. I think so. (In comes the rude man. )R:Hey you there. I need a haircut quickly. Can you do me straightaway?B:All right, then, get in the chair and I'll see what I can do. R:Thank you. (sits down in one of the barber's chairs)H:Excuse me, but I was here first. Aren't you going to do my hair first?B:This man's in a hurry. H:Well so am I!I insist that you cut my hair first. B:OK, but I'll have to be quick. This gentleman is waiting. H:Thank you. (They both become quiet. After his hair is cut, the barber tells Henry how much he must pay. Henry shows the barber the bank note. )B:Why, Mr . . . (looks shocked)H:Adams. Henry Adams. I'm sorry, I don't have any change. R:You're that Mr Adams! Well,I'm glad I waited or I might never have known it was you. B:Why, Mr Adams, please don't worry!(wearing a big smile) Nothing to worry about!Nothing at all!Please come back any time, even if you only need too little hairs cut!It will be my honour to serve you!
Listening and Speaking introduces the topic of “talking about how to become an astronaut”. This period is aimed to inform students some details about the requirements of being an astronaut. Students can be motivated and inspired by the astronauts. Teachers ought to encourage students to learn from them and let them aim high and dream big.Listening and Talking introduces the theme of "talk about life in space". This part also informs students more details about life in space and can inspire students to be curious about this job. 1. Guide students to listen for numbers concerning dates, years and ages etc2. Cultivate students' ability to talk about how to become an astronaut and life in space ; 3. Instruct students to use functional sentences of the dialogue such as “ first of all, I am not sure, so what might be .. I guess.. I wonder…I am curious…)appropriately.1. Guide students to understand the content of listening texts in terms of the whole and key details; 2. Cultivate students' ability to guess the meaning of words in listening; discuss with their peers how to become a qualified astronaut and describe the life in space.Part 1: Listening and SpeakingStep 1: Lead inPredictionThe teacher can ask students to predict what the listening text is about by looking at the pictures.About how to become an astronaut./the requirements of an astronautStep 2: Then, play the radio which is about an interview a. And after finishing listening for the first time, the students need to solve the following tasks.
另一方面,其余的人反对这个计划,因为它可能会导致一些不好的影响。7.I hold the belief that space exploration not only enable us to understand how the universe began but also help us survived well into the future.我坚信探索太空不仅能够使我们了解宇宙的起源而且能够帮助我们更好地走进未来。8.I think we should spend more time and money exploring space so as to provide new and better solutions to people's shortterm and longterm problems.为了给人类的短期和长期问题提供更新和更好的解决方法,我认为我们应该花更多的时间和金钱来探索太空。9.From my point of view,it is wrong of young people to depend on their telephones too much,which may do harm to both their physical and mental health.在我看来,年轻人过度依赖手机是不对的,因为它们可能会对他们的身心健康都有害。最近你班同学就“人类是否应该进行宇宙探索”这个问题进行了激烈的讨论。有人认为,探索宇宙不仅让人类更好地了解宇宙的发展,还可以用来指导农业生产,以及把一些探索太空的高新技术用于现实生活;也有一些人认为探索太空花掉了大量的人力物力;影响了人们的生活水平。请你根据以下情况写一篇报告并发表自己的观点。注意:1.写作内容应包括以上全部要点,可适当发挥,使上下文连贯;
Everybody wants to get wealth.In today’s material world,making money or becoming wealthy symbolizes a person’s success and capability. Many people just make every effort, pay any price to attain greater wealth. With money,they can buy nice, large apartments in nice neighborhood. With money they can own luxurious cars. Wealth seems to bring all happiness in life.But is wealth the only road to happiness? Not really. There are many things in the world, which are beyond the means of money, such as friendship, love, health and knowledge. People are so preoccupied with struggling for money that they have no time or would not take the time to form or maintain friendship. What happiness can they feel living as lonely miserable creatures without love or friends in the world even if they accumulate tremendous wealth?In my opinion, people can’t do anything without money, but money is not everything. What money will bring you depends on your personal belief and goal in life. If you are kind enough to help others, especially the poor, money is a good thing to you. With it, you can do much more for the benefit of people and your country, and it will add to your own happiness. If you want money just for your own needs, you’ll never be satisfied or happy. In a word,you should have money spent for more people. Only then can money be the source of your happiness.Step 8 Homework4 students in a group, one acts Roderick, one Oliver, one servant and the fourth one acts Henry Adams, then listen to the tape, pay more attention to the difference between American English and British English in pronunciation, stress, tone.
一、情境导学前面我们已经得到了两点间的距离公式,点到直线的距离公式,关于平面上的距离问题,两条直线间的距离也是值得研究的。思考1:立定跳远测量的什么距离?A.两平行线的距离 B.点到直线的距离 C. 点到点的距离二、探究新知思考2:已知两条平行直线l_1,l_2的方程,如何求l_1 〖与l〗_2间的距离?根据两条平行直线间距离的含义,在直线l_1上取任一点P(x_0,y_0 ),,点P(x_0,y_0 )到直线l_2的距离就是直线l_1与直线l_2间的距离,这样求两条平行线间的距离就转化为求点到直线的距离。两条平行直线间的距离1. 定义:夹在两平行线间的__________的长.公垂线段2. 图示: 3. 求法:转化为点到直线的距离.1.原点到直线x+2y-5=0的距离是( )A.2 B.3 C.2 D.5D [d=|-5|12+22=5.选D.]
(1)几何法它是利用图形的几何性质,如圆的性质等,直接求出圆的圆心和半径,代入圆的标准方程,从而得到圆的标准方程.(2)待定系数法由三个独立条件得到三个方程,解方程组以得到圆的标准方程中三个参数,从而确定圆的标准方程.它是求圆的方程最常用的方法,一般步骤是:①设——设所求圆的方程为(x-a)2+(y-b)2=r2;②列——由已知条件,建立关于a,b,r的方程组;③解——解方程组,求出a,b,r;④代——将a,b,r代入所设方程,得所求圆的方程.跟踪训练1.已知△ABC的三个顶点坐标分别为A(0,5),B(1,-2),C(-3,-4),求该三角形的外接圆的方程.[解] 法一:设所求圆的标准方程为(x-a)2+(y-b)2=r2.因为A(0,5),B(1,-2),C(-3,-4)都在圆上,所以它们的坐标都满足圆的标准方程,于是有?0-a?2+?5-b?2=r2,?1-a?2+?-2-b?2=r2,?-3-a?2+?-4-b?2=r2.解得a=-3,b=1,r=5.故所求圆的标准方程是(x+3)2+(y-1)2=25.
1.两圆x2+y2-1=0和x2+y2-4x+2y-4=0的位置关系是( )A.内切 B.相交 C.外切 D.外离解析:圆x2+y2-1=0表示以O1(0,0)点为圆心,以R1=1为半径的圆.圆x2+y2-4x+2y-4=0表示以O2(2,-1)点为圆心,以R2=3为半径的圆.∵|O1O2|=√5,∴R2-R1<|O1O2|<R2+R1,∴圆x2+y2-1=0和圆x2+y2-4x+2y-4=0相交.答案:B2.圆C1:x2+y2-12x-2y-13=0和圆C2:x2+y2+12x+16y-25=0的公共弦所在的直线方程是 . 解析:两圆的方程相减得公共弦所在的直线方程为4x+3y-2=0.答案:4x+3y-2=03.半径为6的圆与x轴相切,且与圆x2+(y-3)2=1内切,则此圆的方程为( )A.(x-4)2+(y-6)2=16 B.(x±4)2+(y-6)2=16C.(x-4)2+(y-6)2=36 D.(x±4)2+(y-6)2=36解析:设所求圆心坐标为(a,b),则|b|=6.由题意,得a2+(b-3)2=(6-1)2=25.若b=6,则a=±4;若b=-6,则a无解.故所求圆方程为(x±4)2+(y-6)2=36.答案:D4.若圆C1:x2+y2=4与圆C2:x2+y2-2ax+a2-1=0内切,则a等于 . 解析:圆C1的圆心C1(0,0),半径r1=2.圆C2可化为(x-a)2+y2=1,即圆心C2(a,0),半径r2=1,若两圆内切,需|C1C2|=√(a^2+0^2 )=2-1=1.解得a=±1. 答案:±1 5. 已知两个圆C1:x2+y2=4,C2:x2+y2-2x-4y+4=0,直线l:x+2y=0,求经过C1和C2的交点且和l相切的圆的方程.解:设所求圆的方程为x2+y2+4-2x-4y+λ(x2+y2-4)=0,即(1+λ)x2+(1+λ)y2-2x-4y+4(1-λ)=0.所以圆心为 1/(1+λ),2/(1+λ) ,半径为1/2 √((("-" 2)/(1+λ)) ^2+(("-" 4)/(1+λ)) ^2 "-" 16((1"-" λ)/(1+λ))),即|1/(1+λ)+4/(1+λ)|/√5=1/2 √((4+16"-" 16"(" 1"-" λ^2 ")" )/("(" 1+λ")" ^2 )).解得λ=±1,舍去λ=-1,圆x2+y2=4显然不符合题意,故所求圆的方程为x2+y2-x-2y=0.
【答案】B [由直线方程知直线斜率为3,令x=0可得在y轴上的截距为y=-3.故选B.]3.已知直线l1过点P(2,1)且与直线l2:y=x+1垂直,则l1的点斜式方程为________.【答案】y-1=-(x-2) [直线l2的斜率k2=1,故l1的斜率为-1,所以l1的点斜式方程为y-1=-(x-2).]4.已知两条直线y=ax-2和y=(2-a)x+1互相平行,则a=________. 【答案】1 [由题意得a=2-a,解得a=1.]5.无论k取何值,直线y-2=k(x+1)所过的定点是 . 【答案】(-1,2)6.直线l经过点P(3,4),它的倾斜角是直线y=3x+3的倾斜角的2倍,求直线l的点斜式方程.【答案】直线y=3x+3的斜率k=3,则其倾斜角α=60°,所以直线l的倾斜角为120°.以直线l的斜率为k′=tan 120°=-3.所以直线l的点斜式方程为y-4=-3(x-3).
切线方程的求法1.求过圆上一点P(x0,y0)的圆的切线方程:先求切点与圆心连线的斜率k,则由垂直关系,切线斜率为-1/k,由点斜式方程可求得切线方程.若k=0或斜率不存在,则由图形可直接得切线方程为y=b或x=a.2.求过圆外一点P(x0,y0)的圆的切线时,常用几何方法求解设切线方程为y-y0=k(x-x0),即kx-y-kx0+y0=0,由圆心到直线的距离等于半径,可求得k,进而切线方程即可求出.但要注意,此时的切线有两条,若求出的k值只有一个时,则另一条切线的斜率一定不存在,可通过数形结合求出.例3 求直线l:3x+y-6=0被圆C:x2+y2-2y-4=0截得的弦长.思路分析:解法一求出直线与圆的交点坐标,解法二利用弦长公式,解法三利用几何法作出直角三角形,三种解法都可求得弦长.解法一由{■(3x+y"-" 6=0"," @x^2+y^2 "-" 2y"-" 4=0"," )┤得交点A(1,3),B(2,0),故弦AB的长为|AB|=√("(" 2"-" 1")" ^2+"(" 0"-" 3")" ^2 )=√10.解法二由{■(3x+y"-" 6=0"," @x^2+y^2 "-" 2y"-" 4=0"," )┤消去y,得x2-3x+2=0.设两交点A,B的坐标分别为A(x1,y1),B(x2,y2),则由根与系数的关系,得x1+x2=3,x1·x2=2.∴|AB|=√("(" x_2 "-" x_1 ")" ^2+"(" y_2 "-" y_1 ")" ^2 )=√(10"[(" x_1+x_2 ")" ^2 "-" 4x_1 x_2 "]" ┴" " )=√(10×"(" 3^2 "-" 4×2")" )=√10,即弦AB的长为√10.解法三圆C:x2+y2-2y-4=0可化为x2+(y-1)2=5,其圆心坐标(0,1),半径r=√5,点(0,1)到直线l的距离为d=("|" 3×0+1"-" 6"|" )/√(3^2+1^2 )=√10/2,所以半弦长为("|" AB"|" )/2=√(r^2 "-" d^2 )=√("(" √5 ")" ^2 "-" (√10/2) ^2 )=√10/2,所以弦长|AB|=√10.
反思感悟用基底表示空间向量的解题策略1.空间中,任一向量都可以用一个基底表示,且只要基底确定,则表示形式是唯一的.2.用基底表示空间向量时,一般要结合图形,运用向量加法、减法的平行四边形法则、三角形法则,以及数乘向量的运算法则,逐步向基向量过渡,直至全部用基向量表示.3.在空间几何体中选择基底时,通常选取公共起点最集中的向量或关系最明确的向量作为基底,例如,在正方体、长方体、平行六面体、四面体中,一般选用从同一顶点出发的三条棱所对应的向量作为基底.例2.在棱长为2的正方体ABCD-A1B1C1D1中,E,F分别是DD1,BD的中点,点G在棱CD上,且CG=1/3 CD(1)证明:EF⊥B1C;(2)求EF与C1G所成角的余弦值.思路分析选择一个空间基底,将(EF) ?,(B_1 C) ?,(C_1 G) ?用基向量表示.(1)证明(EF) ?·(B_1 C) ?=0即可;(2)求(EF) ?与(C_1 G) ?夹角的余弦值即可.(1)证明:设(DA) ?=i,(DC) ?=j,(DD_1 ) ?=k,则{i,j,k}构成空间的一个正交基底.
4.已知△ABC三个顶点坐标A(-1,3),B(-3,0),C(1,2),求△ABC的面积S.【解析】由直线方程的两点式得直线BC的方程为 = ,即x-2y+3=0,由两点间距离公式得|BC|= ,点A到BC的距离为d,即为BC边上的高,d= ,所以S= |BC|·d= ×2 × =4,即△ABC的面积为4.5.已知直线l经过点P(0,2),且A(1,1),B(-3,1)两点到直线l的距离相等,求直线l的方程.解:(方法一)∵点A(1,1)与B(-3,1)到y轴的距离不相等,∴直线l的斜率存在,设为k.又直线l在y轴上的截距为2,则直线l的方程为y=kx+2,即kx-y+2=0.由点A(1,1)与B(-3,1)到直线l的距离相等,∴直线l的方程是y=2或x-y+2=0.得("|" k"-" 1+2"|" )/√(k^2+1)=("|-" 3k"-" 1+2"|" )/√(k^2+1),解得k=0或k=1.(方法二)当直线l过线段AB的中点时,A,B两点到直线l的距离相等.∵AB的中点是(-1,1),又直线l过点P(0,2),∴直线l的方程是x-y+2=0.当直线l∥AB时,A,B两点到直线l的距离相等.∵直线AB的斜率为0,∴直线l的斜率为0,∴直线l的方程为y=2.综上所述,满足条件的直线l的方程是x-y+2=0或y=2.
一、情境导学在一条笔直的公路同侧有两个大型小区,现在计划在公路上某处建一个公交站点C,以方便居住在两个小区住户的出行.如何选址能使站点到两个小区的距离之和最小?二、探究新知问题1.在数轴上已知两点A、B,如何求A、B两点间的距离?提示:|AB|=|xA-xB|.问题2:在平面直角坐标系中能否利用数轴上两点间的距离求出任意两点间距离?探究.当x1≠x2,y1≠y2时,|P1P2|=?请简单说明理由.提示:可以,构造直角三角形利用勾股定理求解.答案:如图,在Rt △P1QP2中,|P1P2|2=|P1Q|2+|QP2|2,所以|P1P2|=?x2-x1?2+?y2-y1?2.即两点P1(x1,y1),P2(x2,y2)间的距离|P1P2|=?x2-x1?2+?y2-y1?2.你还能用其它方法证明这个公式吗?2.两点间距离公式的理解(1)此公式与两点的先后顺序无关,也就是说公式也可写成|P1P2|=?x2-x1?2+?y2-y1?2.(2)当直线P1P2平行于x轴时,|P1P2|=|x2-x1|.当直线P1P2平行于y轴时,|P1P2|=|y2-y1|.
(2)l的倾斜角为90°,即l平行于y轴,所以m+1=2m,得m=1.延伸探究1 本例条件不变,试求直线l的倾斜角为锐角时实数m的取值范围.解:由题意知(m"-" 1"-" 1)/(m+1"-" 2m)>0,解得1<m<2.延伸探究2 若将本例中的“N(2m,1)”改为“N(3m,2m)”,其他条件不变,结果如何?解:(1)由题意知(m"-" 1"-" 2m)/(m+1"-" 3m)=1,解得m=2.(2)由题意知m+1=3m,解得m=1/2.直线斜率的计算方法(1)判断两点的横坐标是否相等,若相等,则直线的斜率不存在.(2)若两点的横坐标不相等,则可以用斜率公式k=(y_2 "-" y_1)/(x_2 "-" x_1 )(其中x1≠x2)进行计算.金题典例 光线从点A(2,1)射到y轴上的点Q,经y轴反射后过点B(4,3),试求点Q的坐标及入射光线的斜率.解:(方法1)设Q(0,y),则由题意得kQA=-kQB.∵kQA=(1"-" y)/2,kQB=(3"-" y)/4,∴(1"-" y)/2=-(3"-" y)/4.解得y=5/3,即点Q的坐标为 0,5/3 ,∴k入=kQA=(1"-" y)/2=-1/3.(方法2)设Q(0,y),如图,点B(4,3)关于y轴的对称点为B'(-4,3), kAB'=(1"-" 3)/(2+4)=-1/3,由题意得,A、Q、B'三点共线.从而入射光线的斜率为kAQ=kAB'=-1/3.所以,有(1"-" y)/2=(1"-" 3)/(2+4),解得y=5/3,点Q的坐标为(0,5/3).
1.直线2x+y+8=0和直线x+y-1=0的交点坐标是( )A.(-9,-10) B.(-9,10) C.(9,10) D.(9,-10)解析:解方程组{■(2x+y+8=0"," @x+y"-" 1=0"," )┤得{■(x="-" 9"," @y=10"," )┤即交点坐标是(-9,10).答案:B 2.直线2x+3y-k=0和直线x-ky+12=0的交点在x轴上,则k的值为( )A.-24 B.24 C.6 D.± 6解析:∵直线2x+3y-k=0和直线x-ky+12=0的交点在x轴上,可设交点坐标为(a,0),∴{■(2a"-" k=0"," @a+12=0"," )┤解得{■(a="-" 12"," @k="-" 24"," )┤故选A.答案:A 3.已知直线l1:ax+y-6=0与l2:x+(a-2)y+a-1=0相交于点P,若l1⊥l2,则点P的坐标为 . 解析:∵直线l1:ax+y-6=0与l2:x+(a-2)y+a-1=0相交于点P,且l1⊥l2,∴a×1+1×(a-2)=0,解得a=1,联立方程{■(x+y"-" 6=0"," @x"-" y=0"," )┤易得x=3,y=3,∴点P的坐标为(3,3).答案:(3,3) 4.求证:不论m为何值,直线(m-1)x+(2m-1)y=m-5都通过一定点. 证明:将原方程按m的降幂排列,整理得(x+2y-1)m-(x+y-5)=0,此式对于m的任意实数值都成立,根据恒等式的要求,m的一次项系数与常数项均等于零,故有{■(x+2y"-" 1=0"," @x+y"-" 5=0"," )┤解得{■(x=9"," @y="-" 4"." )┤
解析:①过原点时,直线方程为y=-34x.②直线不过原点时,可设其方程为xa+ya=1,∴4a+-3a=1,∴a=1.∴直线方程为x+y-1=0.所以这样的直线有2条,选B.答案:B4.若点P(3,m)在过点A(2,-1),B(-3,4)的直线上,则m= . 解析:由两点式方程得,过A,B两点的直线方程为(y"-(-" 1")" )/(4"-(-" 1")" )=(x"-" 2)/("-" 3"-" 2),即x+y-1=0.又点P(3,m)在直线AB上,所以3+m-1=0,得m=-2.答案:-2 5.直线ax+by=1(ab≠0)与两坐标轴围成的三角形的面积是 . 解析:直线在两坐标轴上的截距分别为1/a 与 1/b,所以直线与坐标轴围成的三角形面积为1/(2"|" ab"|" ).答案:1/(2"|" ab"|" )6.已知三角形的三个顶点A(0,4),B(-2,6),C(-8,0).(1)求三角形三边所在直线的方程;(2)求AC边上的垂直平分线的方程.解析(1)直线AB的方程为y-46-4=x-0-2-0,整理得x+y-4=0;直线BC的方程为y-06-0=x+8-2+8,整理得x-y+8=0;由截距式可知,直线AC的方程为x-8+y4=1,整理得x-2y+8=0.(2)线段AC的中点为D(-4,2),直线AC的斜率为12,则AC边上的垂直平分线的斜率为-2,所以AC边的垂直平分线的方程为y-2=-2(x+4),整理得2x+y+6=0.
材料说明了什么?探究二:材料分析:2005年12月13日至18日,WTO第六次部长级会议在香港召开。会议经过谈判通过了《部长宣言》,规定发达成员和部分发展中成员2008年前向最不发达国家所有产品提供免关税、免配额的市场准入;发达成员2006年取消棉花的出口补贴, 2013年年底前取消所有形式农产品出口补贴。材料体现了世界贸易组织在国际经济贸易领域中发挥哪些作用?探究三:P97:A、这些图示,反映出我国利用外资哪些特点?。B、能为我国提高外资利用水平提出些建议吗?探究四:材料展示:我国是人口众多的发展中大国,全国居民每天消费总额达到37亿元。每天消费粮食75万吨,相当于一个县级商品粮基地的全年产量;每天消耗猪肉6万吨,食油1万吨,糖1.6万吨,鲜蛋1.8万吨。每天购买杂志600多万册,报纸5000多万份,需要400量中型载货汽车才能装载。
思考提示在阶级社会中,社会基本矛盾的解决主要是通过阶级斗争实现的,阶级斗争是推动阶级社会发展的直接动力,当旧的生产关系严重阻碍生产力发展,需要进行变革时,代表旧的生产关系的没落阶级却不会自动退出历史舞台,利用旧的上层建筑维护自己的统治,只有代表新生产力发展方向的阶级通过社会革命,推翻没落的阶级统治,才能解放生产力,推动社会向前发展。所以,阶级社会的进步往往是通过激烈的社会革命实现的。但是,社会主义社会与阶级社会不同,这是因为,社会主义社会中,生产力和生产关系、经济基础和上层建筑之间的矛盾是一种非对抗性矛盾,不需要通过一个阶级推翻另一个阶级的阶级斗争的方式来解决,只能通过改革实现社会的发展,通过对生产关系和上层建筑进行改革,实现社会主义的自我完善,从而促进社会的发展。所以,我国经济体制改革是在坚持社会主义制度的前提下,改革生产关系和上层建筑中不适应生产力发展的一系列相互联系的环节和方面。
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