This section guides students to pay attention to the typical context of vocabulary use, helps students accumulate vocabulary around the key vocabulary of this unit, and uses the learned words and word chunks in different contexts to deeply understand their meaning and usage, so as to achieve the purpose of review and consolidation.The teaching design activities aim to guide students to pay attention to the typical context in which the target vocabulary is used, as well as the common vocabulary used in collocation, so that students can complete the sentence with correct words. In terms of vocabulary learning strategies, this unit focuses on cultivating students' ability to pay attention to collocation of words and to use word blocks to express meaning.For vocabulary learning, it is not enough just to know the meaning of a single word, but the most important thing is to master the common collocations of words, namely word blocks.Teachers should timely guide students to summarize common vocabulary collocation, such as verb and noun collocation, verb and preposition collocation, preposition and noun collocation, and so on.1. Guide students to understand and consolidate the meaning and usage of the vocabulary in the context, 2. Guide the students to use the unit topic vocabulary in a richer context3. Let the students sort out and accumulate the accumulated vocabulary, establishes the semantic connection between the vocabulary,4. Enable students to understand and master the vocabulary more effectivelyGuiding the Ss to use unit topic words and the sentence patterns in a richer context.
The theme of the listening section is " talking about scenery and culture along a journey."The part is designed to further lead the students to understand Canadian natural geography and social environment, and integrated into the cultural contrast by mentioning the long train journey from Beijing to Moscow routes. On this basis, the part activates students related travel experience, lets the student serial dialogue, guides the student to explore further the pleasure and meaning of the long journey, and Chinese and foreign cultural comparison.The part also provides a framework for the continuation of the dialogue, which is designed to provide a framework for students to successfully complete their oral expressions, and to incorporate an important trading strategy to end the dialogue naturally.1. Help students to understand and master some common English idioms in the context, and experience the expression effect of English idioms.2. Guide the students to understand the identity of different people in the listening context, and finish the dialogue according to their own experience.3. Instruct the students to use appropriate language to express surprise and curiosity about space and place in the dialogue, and master the oral strategy of ending the dialogue naturally.1. Instruct students to grasp the key information and important details of the dialogue.2. Instruct students to conduct a similar talk on the relevant topic.
The purpose of this section of vocabulary exercises is to consolidate the key words in the first part of the reading text, let the students write the words according to the English definition, and focus on the detection of the meaning and spelling of the new words. The teaching design includes use English definition to explain words, which is conducive to improving students' interest in vocabulary learning, cultivating their sense of English language and thinking in English, and making students willing to use this method to better grasp the meaning of words, expand their vocabulary, and improve their ability of vocabulary application. Besides, the design offers more context including sentences and short passage for students to practice words flexibly.1. Guide students to understand and consolidate the meaning and usage of the vocabulary in the context, 2. Guide the students to use the unit topic vocabulary in a richer context3. Let the students sort out and accumulate the accumulated vocabulary, establishes the semantic connection between the vocabulary,4. Enable students to understand and master the vocabulary more effectivelyGuiding the Ss to use unit topic words and the sentence patterns in a richer context.Step1: Read the passage about chemical burns and fill in the blanks with the correct forms of the words in the box.
The theme of this section is to learn how to make emergency calls. Students should learn how to make emergency calls not only in China, but also in foreign countries in English, so that they can be prepared for future situations outside the home.The emergency telephone number is a vital hotline, which should be the most clear, rapid and effective communication with the acute operator.This section helps students to understand the emergency calls in some countries and the precautions for making emergency calls. Through the study of this section, students can accumulate common expressions and sentence patterns in this context. 1.Help students accumulate emergency telephone numbers in different countries and learn more about first aid2.Guide the students to understand the contents and instructions of the telephone, grasp the characteristics of the emergency telephone and the requirements of the emergency telephone.3.Guide students to understand the first aid instructions of the operators.4.Enable Ss to make simulated emergency calls with their partners in the language they have learned1. Instruct students to grasp the key information and important details of the dialogue.2. Instruct students to conduct a similar talk on the relevant topic.Step1:Look and discuss:Match the pictures below to the medical emergencies, and then discuss the questions in groups.
4.有8种不同的菜种,任选4种种在不同土质的4块地里,有 种不同的种法. 解析:将4块不同土质的地看作4个不同的位置,从8种不同的菜种中任选4种种在4块不同土质的地里,则本题即为从8个不同元素中任选4个元素的排列问题,所以不同的种法共有A_8^4 =8×7×6×5=1 680(种).答案:1 6805.用1、2、3、4、5、6、7这7个数字组成没有重复数字的四位数.(1)这些四位数中偶数有多少个?能被5整除的有多少个?(2)这些四位数中大于6 500的有多少个?解:(1)偶数的个位数只能是2、4、6,有A_3^1种排法,其他位上有A_6^3种排法,由分步乘法计数原理,知共有四位偶数A_3^1·A_6^3=360(个);能被5整除的数个位必须是5,故有A_6^3=120(个).(2)最高位上是7时大于6 500,有A_6^3种,最高位上是6时,百位上只能是7或5,故有2×A_5^2种.由分类加法计数原理知,这些四位数中大于6 500的共有A_6^3+2×A_5^2=160(个).
探究新知问题1:已知100件产品中有8件次品,现从中采用有放回方式随机抽取4件.设抽取的4件产品中次品数为X,求随机变量X的分布列.(1):采用有放回抽样,随机变量X服从二项分布吗?采用有放回抽样,则每次抽到次品的概率为0.08,且各次抽样的结果相互独立,此时X服从二项分布,即X~B(4,0.08).(2):如果采用不放回抽样,抽取的4件产品中次品数X服从二项分布吗?若不服从,那么X的分布列是什么?不服从,根据古典概型求X的分布列.解:从100件产品中任取4件有 C_100^4 种不同的取法,从100件产品中任取4件,次品数X可能取0,1,2,3,4.恰有k件次品的取法有C_8^k C_92^(4-k)种.一般地,假设一批产品共有N件,其中有M件次品.从N件产品中随机抽取n件(不放回),用X表示抽取的n件产品中的次品数,则X的分布列为P(X=k)=CkM Cn-kN-M CnN ,k=m,m+1,m+2,…,r.其中n,N,M∈N*,M≤N,n≤N,m=max{0,n-N+M},r=min{n,M},则称随机变量X服从超几何分布.
二项式定理形式上的特点(1)二项展开式有n+1项,而不是n项.(2)二项式系数都是C_n^k(k=0,1,2,…,n),它与二项展开式中某一项的系数不一定相等.(3)二项展开式中的二项式系数的和等于2n,即C_n^0+C_n^1+C_n^2+…+C_n^n=2n.(4)在排列方式上,按照字母a的降幂排列,从第一项起,次数由n次逐项减少1次直到0次,同时字母b按升幂排列,次数由0次逐项增加1次直到n次.1.判断(正确的打“√”,错误的打“×”)(1)(a+b)n展开式中共有n项. ( )(2)在公式中,交换a,b的顺序对各项没有影响. ( )(3)Cknan-kbk是(a+b)n展开式中的第k项. ( )(4)(a-b)n与(a+b)n的二项式展开式的二项式系数相同. ( )[解析] (1)× 因为(a+b)n展开式中共有n+1项.(2)× 因为二项式的第k+1项Cknan-kbk和(b+a)n的展开式的第k+1项Cknbn-kak是不同的,其中的a,b是不能随便交换的.(3)× 因为Cknan-kbk是(a+b)n展开式中的第k+1项.(4)√ 因为(a-b)n与(a+b)n的二项式展开式的二项式系数都是Crn.[答案] (1)× (2)× (3)× (4)√
2.某小组有20名射手,其中1,2,3,4级射手分别为2,6,9,3名.又若选1,2,3,4级射手参加比赛,则在比赛中射中目标的概率分别为0.85,0.64,0.45,0.32,今随机选一人参加比赛,则该小组比赛中射中目标的概率为________. 【解析】设B表示“该小组比赛中射中目标”,Ai(i=1,2,3,4)表示“选i级射手参加比赛”,则P(B)= P(Ai)P(B|Ai)= 2/20×0.85+ 6/20 ×0.64+ 9/20×0.45+ 3/20×0.32=0.527 5.答案:0.527 53.两批相同的产品各有12件和10件,每批产品中各有1件废品,现在先从第1批产品中任取1件放入第2批中,然后从第2批中任取1件,则取到废品的概率为________. 【解析】设A表示“取到废品”,B表示“从第1批中取到废品”,有P(B)= 112,P(A|B)= 2/11 ,P(A| )= 1/11所以P(A)=P(B)P(A|B)+P( )P(A| )4.有一批同一型号的产品,已知其中由一厂生产的占 30%, 二厂生产的占 50% , 三厂生产的占 20%, 又知这三个厂的产品次品率分别为2% , 1%, 1%,问从这批产品中任取一件是次品的概率是多少?
(2)方法一:第一次取到一件不合格品,还剩下99件产品,其中有4件不合格品,95件合格品,于是第二次又取到不合格品的概率为4/99,由于这是一个条件概率,所以P(B|A)=4/99.方法二:根据条件概率的定义,先求出事件A,B同时发生的概率P(AB)=(C_5^2)/(C_100^2 )=1/495,所以P(B|A)=(P"(" AB")" )/(P"(" A")" )=(1/495)/(5/100)=4/99.6.在某次考试中,要从20道题中随机地抽出6道题,若考生至少答对其中的4道题即可通过;若至少答对其中5道题就获得优秀.已知某考生能答对其中10道题,并且知道他在这次考试中已经通过,求他获得优秀成绩的概率.解:设事件A为“该考生6道题全答对”,事件B为“该考生答对了其中5道题而另一道答错”,事件C为“该考生答对了其中4道题而另2道题答错”,事件D为“该考生在这次考试中通过”,事件E为“该考生在这次考试中获得优秀”,则A,B,C两两互斥,且D=A∪B∪C,E=A∪B,由古典概型的概率公式及加法公式可知P(D)=P(A∪B∪C)=P(A)+P(B)+P(C)=(C_10^6)/(C_20^6 )+(C_10^5 C_10^1)/(C_20^6 )+(C_10^4 C_10^2)/(C_20^6 )=(12" " 180)/(C_20^6 ),P(E|D)=P(A∪B|D)=P(A|D)+P(B|D)=(P"(" A")" )/(P"(" D")" )+(P"(" B")" )/(P"(" D")" )=(210/(C_20^6 ))/((12" " 180)/(C_20^6 ))+((2" " 520)/(C_20^6 ))/((12" " 180)/(C_20^6 ))=13/58,即所求概率为13/58.
3.某县农民月均收入服从N(500,202)的正态分布,则此县农民月均收入在500元到520元间人数的百分比约为 . 解析:因为月收入服从正态分布N(500,202),所以μ=500,σ=20,μ-σ=480,μ+σ=520.所以月均收入在[480,520]范围内的概率为0.683.由图像的对称性可知,此县农民月均收入在500到520元间人数的百分比约为34.15%.答案:34.15%4.某种零件的尺寸ξ(单位:cm)服从正态分布N(3,12),则不属于区间[1,5]这个尺寸范围的零件数约占总数的 . 解析:零件尺寸属于区间[μ-2σ,μ+2σ],即零件尺寸在[1,5]内取值的概率约为95.4%,故零件尺寸不属于区间[1,5]内的概率为1-95.4%=4.6%.答案:4.6%5. 设在一次数学考试中,某班学生的分数X~N(110,202),且知试卷满分150分,这个班的学生共54人,求这个班在这次数学考试中及格(即90分及90分以上)的人数和130分以上的人数.解:μ=110,σ=20,P(X≥90)=P(X-110≥-20)=P(X-μ≥-σ),∵P(X-μσ)≈2P(X-μ130)=P(X-110>20)=P(X-μ>σ),∴P(X-μσ)≈0.683+2P(X-μ>σ)=1,∴P(X-μ>σ)=0.158 5,即P(X>130)=0.158 5.∴54×0.158 5≈9(人),即130分以上的人数约为9人.
解析:因为减法和除法运算中交换两个数的位置对计算结果有影响,所以属于组合的有2个.答案:B2.若A_n^2=3C_(n"-" 1)^2,则n的值为( )A.4 B.5 C.6 D.7 解析:因为A_n^2=3C_(n"-" 1)^2,所以n(n-1)=(3"(" n"-" 1")(" n"-" 2")" )/2,解得n=6.故选C.答案:C 3.若集合A={a1,a2,a3,a4,a5},则集合A的子集中含有4个元素的子集共有 个. 解析:满足要求的子集中含有4个元素,由集合中元素的无序性,知其子集个数为C_5^4=5.答案:54.平面内有12个点,其中有4个点共线,此外再无任何3点共线,以这些点为顶点,可得多少个不同的三角形?解:(方法一)我们把从共线的4个点中取点的多少作为分类的标准:第1类,共线的4个点中有2个点作为三角形的顶点,共有C_4^2·C_8^1=48(个)不同的三角形;第2类,共线的4个点中有1个点作为三角形的顶点,共有C_4^1·C_8^2=112(个)不同的三角形;第3类,共线的4个点中没有点作为三角形的顶点,共有C_8^3=56(个)不同的三角形.由分类加法计数原理,不同的三角形共有48+112+56=216(个).(方法二 间接法)C_12^3-C_4^3=220-4=216(个).
The theme of this part is to write an article about healthy diet. Through reading and writing activities, students can accumulate knowledge about healthy diet, deepen their understanding of the theme of healthy diet, and reflect on their own eating habits. This text describes the basic principles of healthy diet. The author uses data analysis, definition, comparison, examples and other methods. It also provides a demonstration of the use of conjunctions, which provides important information reference for students to complete the next collaborative task, writing skills, vivid language materials and expressions.1. Teach Ss to learn and skillfully use the new words learned from the text.2. Develop students’ ability to understand, extract and summarize information.3. Guide students to understand the theme of healthy diet and reflect on their own eating habits.4. To guide students to analyze and understand the reading discourse from the aspects of theme content, writing structure, language expression, etc., 5. Enable Ss to write in combination with relevant topics and opinions, and to talk about their eating habits.1. Guide students to analyze and understand the reading discourse from the aspects of theme content, writing structure, language expression, etc.2. Enable them to write in combination with relevant topics and opinions, and to talk about their eating habits.3. Guide the students to use the cohesive words correctly, strengthen the textual cohesion, and make the expression fluent and the thinking clear.Step1: Warming upbrainstorm some healthy eating habits.1.Eat slowly.2.Don’t eat too much fat or sugar.3.Eat healthy food.4.Have a balanced diet.Step2: Read the passage and then sum up the main idea of each paragraph.
假定你是英国的Jack,打算来中国旅行,请你给你的中国笔友李华写一封信,要点如下:1.你的旅行计划:北京→泰山→杭州;2.征求建议并询问他是否愿意充当你的导游。注意:1.词数80左右(开头和结尾已给出,不计入总词数);2.可以适当增加细节,以使行文连贯。参考词汇:故宫 the Forbidden City;泰山 Mount TaiDear Li Hua,I'm glad to tell you that 'm going to visit China.First,I am planning to visit Beijing,the capitalof China,where I am looking forward to enjoying the Great Wall,the Forbidden City and somebeautiful parks.Then I intend to go to visit Mount Tai in Shandong Province.I've heard that it is one ofthe most famous mountains in China and I can't wait to enjoy the amazing sunrise there.After that,I amalso going to Hangzhou.It is said that it is a beautiful modern city with breathtaking natural sights,among which the West Lake is a well- known tourist attraction.What do you think of my travel plan? Will you act as my guide? Hope to hear from you soon.
The theme of this activity is to learn the first aid knowledge of burns. Burns is common in life, but there are some misunderstandings in manual treatment. This activity provides students with correct first aid methods, so as not to take them for granted in an emergency. This section guides students to analyze the causes of scald and help students avoid such things. From the perspective of text structure and collaborative features, the text is expository. Expository, with explanation as the main way of expression, transmits knowledge and information to readers by analyzing concepts and elaborating examples. This text arranges the information in logical order, clearly presents three parts of the content through the subtitle, accurately describes the causes, types, characteristics and first aid measures of burns, and some paragraphs use topic sentences to summarize the main idea, and the level is very clear.1. Guide students to understand the causes, types, characteristics and first aid methods of burns, through reading2. Enhance students’ ability to deal withburnss and their awareness of burns prevention3. Enable students to improve the ability to judge the types of texts accurately and to master the characteristics and writing techniques of expository texts.Guide students to understand the causes, types, characteristics and first aid methods of burns, through readingStep1: Lead in by discussing the related topic:1. What first-aid techniques do you know of ?CPR; mouth to mouth artificial respiration; the Heimlich Manoeuvre
问题1. 用一个大写的英文字母或一个阿拉伯数字给教室里的一个座位编号,总共能编出多少种不同的号码?因为英文字母共有26个,阿拉伯数字共有10个,所以总共可以编出26+10=36种不同的号码.问题2.你能说说这个问题的特征吗?上述计数过程的基本环节是:(1)确定分类标准,根据问题条件分为字母号码和数字号码两类;(2)分别计算各类号码的个数;(3)各类号码的个数相加,得出所有号码的个数.你能举出一些生活中类似的例子吗?一般地,有如下分类加法计数原理:完成一件事,有两类办法. 在第1类办法中有m种不同的方法,在第2类方法中有n种不同的方法,则完成这件事共有:N= m+n种不同的方法.二、典例解析例1.在填写高考志愿时,一名高中毕业生了解到,A,B两所大学各有一些自己感兴趣的强项专业,如表,
尊敬的各位评委、各位老师,大家好,我今天说课的内容是九年义务教育人教版小学数学一年级上册第四单元《认识图形》的第一课时——认识图形。下面我将从说教材、说教法与学法、说教学过程和说板书设计这四方面来谈谈我对本课的教学设想。一、说教材: 1、教材分析 首先我对本教才进行简单的分析,课程标准把空间与图形作为义务教育阶段培养学生初步创新精神和实践能力的一个重要的学习内容。《认识图行》是本册教材《认识图形》的起始课,旨在认识长方体、正方体、圆柱和球这些立体图形,认识这几种图形有助于发展学生的空间观念,培养学生初步的观察能力,动手操作能力和交流能力。 2、说教学目标 依据一年级学生的心理特点和的认知能力,我确定了以下教学目标: 1、知识与技能:通过观察操作,初步认识长方体,正方体,球和圆柱体。 2、过程与方法:在观察、操作、比较等活动过程中,培养学生抽象、概括、实践、创新能力,建立空间观念。
尊敬的老师们、亲爱的同学们,大家早上好,我是高二(3)班的童xx,今天我演讲的题目是“驱赶秋日的寒意,点燃运动的热情”。为了丰富校园文化生活,展示学校教育成果,促进学生德智体美劳全面发展,本周我校将举行秋季运动会。这将是一次展示力与美的盛会,也将是一次体魄与耐力的比拼。运动会是检验学校水平高低的一个标志,也是各个班级、每位同学展示风采的一个舞台。运动会是一个竞技场,优胜劣汰,容不得半点虚假。同一起跑线上,你付出多少汗水,就会有多少回报。没有顽强的拼搏,不会有优异的成果;没有坚定的信心,跑道上不会有你亮丽的身影。体育舞台是人生舞台的一个缩影,鲜花和掌声是献给脚踏实地、顽强拼搏、不畏艰难的人。“重在参与”展现着我们的积极心态,“为班争光”蕴含着我们的集体主义情怀,赛场上人人都是胜利者,结果并不重要智力与体力才是我们追求的目标。运动会不仅可以检验我们的运动水平和班级凝聚力,还可以充分展示我校同学朝气蓬勃的精神面貌。运动会不仅比运动水平运动精神与全校师生对德、智、体全面发展的教育方针的全面理解。
《函数的单调性与最大(小)值》是高中数学新教材第一册第三章第2节的内容。在此之前,学生已学习了函数的概念、定义域、值域及表示法,这为过渡到本节的学习起着铺垫作用。学生在初中已经学习了一次函数、二次函数、反比例函数的图象,在此基础上学生对增减性有一个初步的感性认识,所以本节课是学生数学思想的一次重要提高。函数单调性是函数概念的延续和拓展,又是后续研究指数函数、对数函数等内容的基础,对进一步研究闭区间上的连续函数最大值和最小值的求法和实际应用,对解决各种数学问题有着广泛作用。课程目标1、理解增函数、减函数 的概念及函数单调性的定义;2、会根据单调定义证明函数单调性;3、理解函数的最大(小)值及其几何意义;4、学会运用函数图象理解和研究函数的性质.数学学科素养
为了让学生灵活地掌握知识,在这我设计了一个“摆花片“的活动,让学生拿出1个黄色花片和7个红色花片,学生任意摆成一行,摆好后说一说是怎样摆的,黄花片摆在第几,并鼓励学生向同桌介绍一下自已的摆法。(通过这一活动,培养费了学生的动手能力,语言表达能力和思维能力)四、巩固练习1、基础练习:课本23页练一练第1题,“共有()朵花,从左数分别把第2朵和第6朵涂上不同的颜色,让学生进一步巩固几个和第几的含义。2、针对性练习:右以让学生说说各位车手的名次,再连线,这道题的侧重点是比赛地顺序。有针对性的巩固第几的含义。3、综合应用练习:最后组织学生做游戏,从左数第3排的同学站起来;对着老师这排的前4个同学丫起来,对着老师这排的第5个同学举一下手等等。通过游戏让学生巩固几个和第几的含义,同时让学生感受爱到数学就在身边。五、全课小结:通过这节课的学心,你有什么收获?总之,这节课我让学生动口、动脑、动手,在精心设计的数学活动中学习数学。
1、利用色彩、粗细、疏密、节奏不同的点、线条及细小的形状、创造性的表现不同的雨及雨中的情景。2、尝试体验下雨给人与动物带来的不同感受。3、引导学生回忆下雨时的情景,感受人间亲情、友情以及人与自然的关系。
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